Forum Discussion
Min & Max Value within a date range
- Anonymous4 years ago
Hi BryceBicknell ,
Please try:
MIN_A = MINX(DATESINPERIOD('Calendar'[Date],MAX('Calendar'[Date]),-365,DAY),[A])MAX_A = MAXX(DATESINPERIOD('Calendar'[Date],MAX('Calendar'[Date]),-365,DAY),[A])Best Regards,
Gao
Community Support TeamIf there is any post helps, then please consider Accept it as the solution to help the other members find it more quickly. If I misunderstand your needs or you still have problems on it, please feel free to let us know. Thanks a lot!
How to get your questions answered quickly -- How to provide sample data
What I want to do is use it for the Axis min and max range, yes I do have a date table.
Below is an example of the data what my Min value should be is 2 and max should be 18 within those dates below, the main difference is my data set has hundreds of stores. So smallest sum of all stores for the min and the largest sum of all stores for the max.
| Store Number | Store Name | Store Open Date | Area | Region | State | Total | Date | Sales |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Wednesday, 2 August 2017 | 1 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Thursday, 3 August 2017 | 2 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Friday, 4 August 2017 | 3 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Saturday, 5 August 2017 | 4 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Sunday, 6 August 2017 | 5 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Monday, 7 August 2017 | 6 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Tuesday, 8 August 2017 | 7 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Wednesday, 9 August 2017 | 8 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Thursday, 10 August 2017 | 9 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Wednesday, 2 August 2017 | 1 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Thursday, 3 August 2017 | 2 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Friday, 4 August 2017 | 3 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Saturday, 5 August 2017 | 4 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Sunday, 6 August 2017 | 5 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Monday, 7 August 2017 | 6 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Tuesday, 8 August 2017 | 7 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Wednesday, 9 August 2017 | 8 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Thursday, 10 August 2017 | 9 |
Hi BryceBicknell ,
Please try:
MIN_A = MINX(DATESINPERIOD('Calendar'[Date],MAX('Calendar'[Date]),-365,DAY),[A])MAX_A = MAXX(DATESINPERIOD('Calendar'[Date],MAX('Calendar'[Date]),-365,DAY),[A])
Best Regards,
Gao
Community Support Team
If there is any post helps, then please consider Accept it as the solution to help the other members find it more quickly. If I misunderstand your needs or you still have problems on it, please feel free to let us know. Thanks a lot!
How to get your questions answered quickly -- How to provide sample data