Forum Discussion
Min & Max Value within a date range
- Anonymous4 years ago
Hi BryceBicknell ,
Please try:
MIN_A = MINX(DATESINPERIOD('Calendar'[Date],MAX('Calendar'[Date]),-365,DAY),[A])MAX_A = MAXX(DATESINPERIOD('Calendar'[Date],MAX('Calendar'[Date]),-365,DAY),[A])Best Regards,
Gao
Community Support TeamIf there is any post helps, then please consider Accept it as the solution to help the other members find it more quickly. If I misunderstand your needs or you still have problems on it, please feel free to let us know. Thanks a lot!
How to get your questions answered quickly -- How to provide sample data
Hi BryceBicknell ,
How do you intend to use the min and max values in a line chart - as a dimension or a fact? And what is your basis for calculating what dates are within 365 days? Can you please share sample data and your expected result.
What I want to do is use it for the Axis min and max range, yes I do have a date table.
Below is an example of the data what my Min value should be is 2 and max should be 18 within those dates below, the main difference is my data set has hundreds of stores. So smallest sum of all stores for the min and the largest sum of all stores for the max.
| Store Number | Store Name | Store Open Date | Area | Region | State | Total | Date | Sales |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Wednesday, 2 August 2017 | 1 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Thursday, 3 August 2017 | 2 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Friday, 4 August 2017 | 3 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Saturday, 5 August 2017 | 4 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Sunday, 6 August 2017 | 5 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Monday, 7 August 2017 | 6 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Tuesday, 8 August 2017 | 7 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Wednesday, 9 August 2017 | 8 |
| 1234 | ABC | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Thursday, 10 August 2017 | 9 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Wednesday, 2 August 2017 | 1 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Thursday, 3 August 2017 | 2 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Friday, 4 August 2017 | 3 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Saturday, 5 August 2017 | 4 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Sunday, 6 August 2017 | 5 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Monday, 7 August 2017 | 6 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Tuesday, 8 August 2017 | 7 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Wednesday, 9 August 2017 | 8 |
| 12345 | ABCD | Friday, 29 April 2022 | XXXX | XXXX | XXXX | -159 | Thursday, 10 August 2017 | 9 |
- Anonymous4 years agoNot applicable
Hi BryceBicknell ,
Please try:
MIN_A = MINX(DATESINPERIOD('Calendar'[Date],MAX('Calendar'[Date]),-365,DAY),[A])MAX_A = MAXX(DATESINPERIOD('Calendar'[Date],MAX('Calendar'[Date]),-365,DAY),[A])Best Regards,
Gao
Community Support TeamIf there is any post helps, then please consider Accept it as the solution to help the other members find it more quickly. If I misunderstand your needs or you still have problems on it, please feel free to let us know. Thanks a lot!
How to get your questions answered quickly -- How to provide sample data