Measure to divide each data point by the earliest visible data point

[ScottPat]

Probably an easy one for someone out there.

I have some time series data and I want a measure where it forces the result to be 1 on the first time shown in the graph.

So basically it would show the value of the items divided by the first date visible in the report. And when I change the slider to show other dates it changes the value it is dividing by to the one for that start date.

I was using this formula in a column - but this just refers to the first EVER date as opposed to the first visible one.  

LME N = [LME]/calculate(average([LME]) ,filter('Copper',[Date]= min([Date])))

[ScottPat]

Now I get " the value for 'LME' cannot be determined."

I guess this is about row context but not sure how to fix - i ofcourse want the LME value to use each time periods value.

[amitchandak]

@ScottPat , My mistake LME is a measure

LME N =
var _min = minx(allselected('Copper'), [Date])
return

divide([LME], calculate(averagex(Values('Copper'[Date]), [LME]) ,filter('Copper',[Date]= _min)) )

or

LME N =
var _min = minx(allselected('Copper'), [Date])
return

divide([LME], calculate(averagex('Copper', [LME]) ,filter('Copper',[Date]= _min)) )

or use a avg measure

[ScottPat]

No LME is a column not a measure (with the sigma / Sum icon) - so it still doesn't seem quite right in my context.

[ScottPat]

OK I see what i needed, I had a filter context I needed to remove with

all()

[amitchandak · Accepted solution]

@ScottPat , Try like

LME N =
var _min = minx(allselected('Copper'), [Date])
return

[LME]/calculate(average([LME]) ,filter('Copper',[Date]= _min))

prefer a date table joined with date of your table

LME N =
var _min = minx(allselected('Date'), [Date])
return

[LME]/calculate(average([LME]) ,filter('Date',Date[Date]= _min))

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https://amitchandak.medium.com/power-bi-5-key-points-to-make-time-intelligence-successful-bd52912a5b...
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