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Anonymous's avatar
Anonymous
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7 years ago
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Measure for dividing rows within the same column

Hi

 

Hoping for a little assistance on this one. 

 

I have a column with aprox 100.000 rows and 3 different values inside it.

 

I need a measure (or another way) of dividing these values against eachother to give me the percentage difference between them.

 

I have not been able to get it to work.

 

Will appriciate all suggestions

 

Thanks

  • Anonymous ,

     

    To be general, suppose the table is like below.

    You may try these steps, firstly, click Modeling-> New Table and create a summarized table using DAX below(You should add a rank column as index).

    Table = ADDCOLUMNS(VALUES(Table1[Data]), "Rank", RANKX(VALUES(Table1[Data]), Table1[Data], , ASC, Dense))

     

    Then create another table which contains selection value and create a slicer based on that column, finally create a measure in 'Table' using DAX below and drag the measure to a card visual.

       

     

    You may also refer to the appendix.

     

    Community Support Team _ Jimmy Tao

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

1 Reply

  • v-yuta-msft's avatar
    v-yuta-msft
    Icon for Community Support rankCommunity Support

    Anonymous ,

     

    To be general, suppose the table is like below.

    You may try these steps, firstly, click Modeling-> New Table and create a summarized table using DAX below(You should add a rank column as index).

    Table = ADDCOLUMNS(VALUES(Table1[Data]), "Rank", RANKX(VALUES(Table1[Data]), Table1[Data], , ASC, Dense))

     

    Then create another table which contains selection value and create a slicer based on that column, finally create a measure in 'Table' using DAX below and drag the measure to a card visual.

       

     

    You may also refer to the appendix.

     

    Community Support Team _ Jimmy Tao

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.