Forum Discussion
KPI question
Hello all,
I have following situation:
Indicator for KPI is:
- Anonymous5 years ago
Hi Pikachu-Power ,
According to your description, I create this data:
Here are the steps you can follow:
1. Create measure.
When the color is blue, the category is 1 and the maximum date:
Blue_1 = var _1=MAXX(FILTER(ALL('Table'),'Table'[Categorie1]=1&&'Table'[Layer]="Blue"),'Table'[Date]) return CALCULATE(SUM('Table'[Value]),FILTER(ALL('Table'),'Table'[Layer]="Blue"&&'Table'[Date]=_1))When the color is yellow, category is 1 and the maximum date:
Yellow_1 = var _1=MAXX(FILTER(ALL('Table'),'Table'[Categorie1]=1&&'Table'[Layer]="Yellow"),'Table'[Date]) return CALCULATE(SUM('Table'[Value]),FILTER(ALL('Table'),'Table'[Layer]="Yellow"&&'Table'[Date]=_1))2. Result.
You can downloaded PBIX file from here.
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
9 Replies
- amitchandakSuper User
Pikachu-Power , In this blue and yellow should both selected in slicer or none.
Can you share sample data and sample output in table format? Or a sample pbix after removing sensitive data.
- Pikachu-PowerImpactful Individual
Hello all,
I have a sample pbix file in onedrive. But how to load it here? 🤔
- Pikachu-PowerImpactful Individual
hi all,
i couldnt load the pbix file without publihing private data so i will load the images:
you also have to create a calender table and connect with the table. For table i created following two measures:
Clients_Blue = CALCULATE(SUM(Tabelle[Value]),Tabelle[Layer] = "Blue",FILTER(Calender, Calender[Month] = MAX(Calender[Month])))Clients_Yellow = CALCULATE(SUM(Tabelle[Value]),Tabelle[Layer] = "Yellow",FILTER(Calender, Calender[Month] = MAX(Calender[Month])))What I want is to divide the 1800 through 4100. In best case in the KPI and without doing any transformation with the dataset.
- AnonymousNot applicable
Hi Pikachu-Power ,
Here are the steps you can follow:
1. Create measure.
Blue_Max = MAXX(FILTER(ALLSELECTED('Table'),'Table'[Layer]="Blue"),'Table'[Value])Yellow_Max = MAXX(FILTER(ALLSELECTED('Table'),'Table'[Layer]="Yellow"),'Table'[Value])2. Place the Blue_Max and Yellow_Max for comparison on the Indicator and Target goals respectively, and display the date on the Trend axis
3. Result:
You can downloaded PBIX file from here.
This is the related link of KPI, hope to help you:
https://docs.microsoft.com/en-us/power-bi/visuals/power-bi-visualization-kpiBest Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- Pikachu-PowerImpactful Individual
But the SUM is missing:
Clients_Blue = CALCULATE(SUM(Tabelle[Value]),Tabelle[Layer] = "Blue",FILTER(Calender, Calender[Month] = MAX(Calender[Month])))Sorry my table wasnt detailed enough. I have two additional columns Categorie1 and Categorie2 that splits the blue part in 3 tables. So I need the SUM of the MAX.Another point:I need more Filter like Table[Layer]="Blue" and Table[Layer2]="Blue2" and Table[Layer3]="Blue3". But FILTER only accept one argument. Is it possible to complete this?- AnonymousNot applicable
Hi Pikachu-Power ,
Not very clear about your description... If you want more filters like table [layer] = "blue", you can use the in function
Step description:1. First use the summrize function to find a virtual table, which is grouped by Layer and some of the largest values of the date:
2. Use the IN function to select the desired Layer
Here are the steps you can follow:
1. Create measure.
Blue_Yellow = var _summrize= SUMMARIZE('Table','Table'[Layer], "value",MAX('Table'[Value]), "date",MAX('Table'[Date]) ) return CALCULATE(SUM('Table 2'[Value]),FILTER('Table 2','Table 2'[Layer] in {"Blue","Yellow"}))2. Result.
You can downloaded PBIX file from here.
If my answer is not what you need, can you share sample data and sample output in table format? Or a sample pbix after removing sensitive data.
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.