Forum Discussion
Is this Dynamic Value segmentation?
- 4 years ago
Hi ING_BT ,
Based on the description you have you need to do a measure similar to this one:
Count Words on ranking = VAR temptable = SUMMARIZE ( words, Words[Brand], Words[Keyword], "AVerageRanking", AVERAGE ( Words[Rank] ) ) RETURN COUNTROWS ( FILTER ( temptable, [AVerageRanking] <= MAX ( Ranking[End] ) && [AVerageRanking] >= MIN ( Ranking[Start] ) ) )I have added some words counts on the Brand A and has you can see the total word count is 2 always:
Be aware that this calculation is at a brand level if your try to do it with all brands at all ranking the calculation is incorrect has you can see in the Total column below
Hello Félix,
Thank you so much for your help! Your solution is very clear and It works perfectly. And thank you for very detailed explanation.
I spend hours to solution this, you cannot imagine the relief! I understand the logic now (thank you for naming it "temptable", makes it so obvious now!)
All the best,
BT
Hi ING_BT ,
Has I refer the the calculation is made at brand level, if you need to redo this to have all the brands selected and all the words this can be changed.
- ING_BT4 years agoHelper I
Hello Félix,
Yes I understand, thank you!
If I may, I have another question concerning the measure:
How would you change the measure to include all the "Empty ranks" which are considered as "Not Ranked" into a "Not Ranked" interval ?
(obviously this doens't work with the <Max & >= MIN)
It's basicaly to classify everything that as the average = blank()ISBLANK(AVERAGE ( Words[Rank] ))
(PS: it's normal that I put 50 as max in the 21 to 49 formula - the data is not the cleanest)
Best,
BT- MFelix4 years agoSuper User
Hi ING_BT ,
How would this work if the word without ranking have a ranking on another week?
Pciking up your example:
Brand Keyword Rank A
Label 3 A Tutorial 2 B Label 43 B Tutorial 4 C Label 6 C Tutorial 21 C Label C Other How would you consider the Label without ranking on this case would you have the average of the label has 3 since is (6 + 0) / 2 and or would you consider only once label in this case for Company C you would have the wich of the tables below:
Table 1 - Consider only words above 50 the ones that have no ranking (work: Other) all others words are consider the average of the values with ranking (Label - 6 , Tutorial - 21)
Interval Words 1 - 3
0 4 - 10 1 11 - 20 1 21 - 49 0 +50 Others 1 Table 2 - Consider only words above 50 the ones that have no ranking (work: Other) all others words are consider the average of the values (Label - 6/2) , Tutorial - 21)
Interval Words 1 - 3
1 4 - 10 0 11 - 20 1 21 - 49 0 +50 Others 1 Table 3 - Consider words above 50 the ones that have no ranking (work: Other + Label) all others words are consider the average of the values (Label - 6 , Tutorial - 21)
Interval Words 1 - 3
0 4 - 10 1 11 - 20 1 21 - 49 0 +50 Others 2 Wich option do you consider? I know that in the last one we have more words than the distinct words but is to understand if you want to highlight that some words may need to be revised on the ranking.
- ING_BT4 years agoHelper I
I think the Table 2 is the one I am looking for.
As, if for the selected period (with several dates), a brand has no rank at all on 10 keywords; I need to display these 10 keywords inside that +50 Not Ranked interval.
However, if there is a keyword where it has as rank but only on a few dates, it should be counted in the average, example:
Label is in the interval (2+2+10)/3=4.6 => 4 to 10
(empty are (null) and not "0" in the data, which simplyfies things?)10/12 Label (null) 16/12 Label 2 21/12 Label 10 27/12 Label 2 31/12 Label (null) (appologiesfor the late answer)
Thank you!