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Lucy_Ramirez
Frequent Visitor

Incremento por producto

Hola

Me puedes ayudar? Estoy intentando calcular el incremento de precio por tamaño de producto.

Mi tabla esta de la siguiente manera:

 Precio
REFRESCO 16 OZ$55
REFRESCO 22 OZ$60
REFRESCO 32 OZ$65
REFRESCO 44 OZ$70

 

Necesito que mi formula me diga cual es el porcentaje de incremento entre cada tamaño de refresco, me gustaría que la formula me mostrara la formula de incremento:

 PrecioIncremento
REFRESCO 16 OZ$55N/A
REFRESCO 22 OZ$609.09%
REFRESCO 32 OZ$658.33%
REFRESCO 44 OZ$707.69%

 

Muchas gracias!

1 ACCEPTED SOLUTION
v-tangjie-msft
Community Support
Community Support

Hi @Lucy_Ramirez ,

 

According to your description, here are my steps you can follow as a solution.

(1) This is my test data. 

vtangjiemsft_0-1695089429442.png

(2)Click "transform data" to go to the power query editor and add a index column.

(3) We can create a measure. 

Incremento = VAR _a= CALCULATE(MAX('Table'[Precio]),FILTER(ALL('Table'),'Table'[Index]=MAX('Table'[Index])-1))
var _b=MAX('Table'[Precio])
var _c=DIVIDE(_b-_a,_a,0)
return IF(_c=0,"N/A",_c)

(4) Then the result is as follows.

vtangjiemsft_1-1695089542678.png

Best Regards,

Neeko Tang

If this post  helps, then please consider Accept it as the solution  to help the other members find it more quickly. 

View solution in original post

2 REPLIES 2
v-tangjie-msft
Community Support
Community Support

Hi @Lucy_Ramirez ,

 

According to your description, here are my steps you can follow as a solution.

(1) This is my test data. 

vtangjiemsft_0-1695089429442.png

(2)Click "transform data" to go to the power query editor and add a index column.

(3) We can create a measure. 

Incremento = VAR _a= CALCULATE(MAX('Table'[Precio]),FILTER(ALL('Table'),'Table'[Index]=MAX('Table'[Index])-1))
var _b=MAX('Table'[Precio])
var _c=DIVIDE(_b-_a,_a,0)
return IF(_c=0,"N/A",_c)

(4) Then the result is as follows.

vtangjiemsft_1-1695089542678.png

Best Regards,

Neeko Tang

If this post  helps, then please consider Accept it as the solution  to help the other members find it more quickly. 

amitchandak
Super User
Super User

@Lucy_Ramirez , Create a new column

 

New colum =

var _min = minx(filter(Table, [Item] =earlier([Item])), [Size])

var _price= maxx(filter(Table, [Item] =earlier([Item]) && [Size] =_min), [Precio]) 

return

divide([Precio] -_price, _price)

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