Forum Discussion
Anonymous
4 years agoNot applicable
Identify geographic influence
Hello guys. I'm new here and in PB. I work for the Brazillian government in the departament of transports. We are developing a project to relate car accidents registered locations with our middle sc...
- 4 years ago
When we want to calculate the distance between two locations, we need to know the coordinates of these two locations.
Here’s the sample data:
We now have the coordinates of current locations and destinations, using below formula we could get the distance between these locations.
Distince (KM) = 12742 -- The diameter of the Earth (KM). * ASIN ( -- Returns the arcsine, or inverse sine, of a number. SQRT ( -- Returns the square root of a number. POWER ( -- Returns the result of a number raised to a power. SIN ( -- Returns the sine of the given angle. 'Table'[Current Lat] - 'Table'[Destination Lat] ) * PI () / 360, 2 ) -- PI () Returns the value of Pi, 3.14159265358979, accurate to 15 digits. + COS ( -- Returns the cosine of the given angle. 'Table'[Current Lat] * PI () / 180 ) * COS ( 'Table'[Destination Lat] * PI () / 180 ) * POWER ( SIN ( 'Table'[Current Long] - 'Table'[Destination Long] ) * PI () / 360, 2 ) ) )
V-lianl-msft
4 years agoCommunity Support
When we want to calculate the distance between two locations, we need to know the coordinates of these two locations.
Here’s the sample data:
We now have the coordinates of current locations and destinations, using below formula we could get the distance between these locations.
Distince (KM) =
12742 -- The diameter of the Earth (KM).
* ASIN (
-- Returns the arcsine, or inverse sine, of a number.
SQRT (
-- Returns the square root of a number.
POWER (
-- Returns the result of a number raised to a power.
SIN ( -- Returns the sine of the given angle.
'Table'[Current Lat] - 'Table'[Destination Lat] )
* PI () / 360,
2
) -- PI () Returns the value of Pi, 3.14159265358979, accurate to 15 digits.
+ COS (
-- Returns the cosine of the given angle.
'Table'[Current Lat] * PI () / 180
)
* COS ( 'Table'[Destination Lat] * PI () / 180 )
* POWER (
SIN ( 'Table'[Current Long] - 'Table'[Destination Long] )
* PI () / 360,
2
)
)
)
- Anonymous4 years agoNot applicable
Thank you for the tip. It worked very well.