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CSpina
Helper III
Helper III

Howto count customers per salesperson based on customer log (date)

Hi there!

I need to create a visual (matrix) to show the number of customers has per salesman and month. I was able to count the amount in the month, but in subsequent months the value becomes null.

 

CSpina_0-1676029977153.png

I need the a measure to count like that (number is red):

CSpina_1-1676030265659.png

 

 

Loga data

1112021-01-01
2212021-01-01
3312021-01-01
4412021-01-01
5512021-01-01
6312021-01-01
714202-10-09
8232021-11-06
9522021-12-10

 

Any ideas? Thanks in advance.

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi @CSpina ,

 

I suggest you to create a new measure based on [Measure2].

Measure 3 = SUMX(VALUES('Table'[ID]),[Measure 2])

Result is as below.

RicoZhou_0-1677059742022.png

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

3 REPLIES 3
Anonymous
Not applicable

Hi @CSpina ,

 

Here I suggest you to create measures to achieve your goal.

Measure = 
CALCULATE(COUNT('Table'[Column2]),FILTER(ALL('Table'),'Table'[ID] = MAX('Table'[ID])&&'Table'[Date]<=MAX('Date'[Date])))
Measure 2 = 
VAR _A = AVERAGEX(FILTER(ALL('Table'),'Table'[ID] = 1),[Measure])
VAR _B = SUMX(FILTER(ALL('Table'),'Table'[ID] <> 1),[Measure])
RETURN
if(MAX('Table'[ID]) = 1, _A -_B,[Measure])

Result is as below.

RicoZhou_0-1676366863190.png

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

Thank you very much! We are almost there, I need a rows total and could you please send thesample pbix?

Anonymous
Not applicable

Hi @CSpina ,

 

I suggest you to create a new measure based on [Measure2].

Measure 3 = SUMX(VALUES('Table'[ID]),[Measure 2])

Result is as below.

RicoZhou_0-1677059742022.png

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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