Forum Discussion
How to write specific date column?
- 6 years ago
Hi, YunJ
I'd like to suggest you create a calculated column as below. The pbix file is attached in the end.
DateDuration = var _min = CALCULATE( MIN('Date'[Date]), FILTER( ALL('Date'), 'Date'[YearWeeknum]=EARLIER('Date'[YearWeeknum])&& 'Date'[Month]=EARLIER('Date'[Month]) ) ) var _max = CALCULATE( MAX('Date'[Date]), FILTER( ALL('Date'), 'Date'[YearWeeknum]=EARLIER('Date'[YearWeeknum])&& 'Date'[Month]=EARLIER('Date'[Month]) ) ) return _min&"-"&_maxResult:
Best Regards
Allan
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi, YunJ
I'd like to suggest you create a calculated column as below. The pbix file is attached in the end.
DateDuration =
var _min =
CALCULATE(
MIN('Date'[Date]),
FILTER(
ALL('Date'),
'Date'[YearWeeknum]=EARLIER('Date'[YearWeeknum])&&
'Date'[Month]=EARLIER('Date'[Month])
)
)
var _max =
CALCULATE(
MAX('Date'[Date]),
FILTER(
ALL('Date'),
'Date'[YearWeeknum]=EARLIER('Date'[YearWeeknum])&&
'Date'[Month]=EARLIER('Date'[Month])
)
)
return
_min&"-"&_max
Result:
Best Regards
Allan
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- YunJ6 years agoPost Prodigy
- v-alq-msft6 years agoCommunity Support
Hi, YunJ
I'd like to suggest you modify the calculated table as below.
Date = ADDCOLUMNS( ADDCOLUMNS( CALENDAR(DATE(2020,1,1),DATE(2020,12,31)), "Year",YEAR([Date]), "Quarter","Q"&FORMAT([Date],"Q"), "Month",FORMAT([Date],"MM"), "Day",FORMAT([Date],"DD"), "YearQuarter",FORMAT([Date],"YYYY")&"Q"&FORMAT([Date],"Q"), "YearMonth",FORMAT([Date],"YYYY/MM"), "Weekday",WEEKDAY([Date],2), "Weeknum",WEEKNUM([Date],2) ), "YearWeeknum",[Year]*100+[Weeknum], "YearMonthWeeknum",[Year]*100+[Month]*10+[Weeknum] )Then you may make 'DateDuration' column selected, click 'Sort by column' in 'Column tools', sort by 'YearMonthWeeknum'.
Result:
Best Regards
Allan
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.