Forum Discussion
How to split Azure resource tags in to separate columns.
Hi v-ljerr-msft
Sorry for the multiple posts but I think I have had some success. The code below which includes an IF statement at the start does seem to do the trick and doesn't error out when it can not find the key word. It may not be pretty but it seems to do the job, if you could offer any further refinements that would be great but otherwise I think we might have cracked it.
Hostname = IF(SEARCH( "Hostname" ,'Table1-Full'[Tags],,BLANK() ) ,( VAR textLength = SEARCH ( ",", 'Table1-Full'[Tags], SEARCH ( "Hostname", 'Table1-Full'[Tags] ) + LEN ( "Hostname" ) + 3 ) - ( SEARCH ( "Hostname", 'Table1-Full'[Tags] ) + LEN ( "Hostname" ) + 3 ) - 1 RETURN MID ( 'Table1-Full'[Tags], SEARCH ( "Hostname", 'Table1-Full'[Tags] ) + LEN ( "Hostname" ) + 3, textLength )))Thanks
Danny
Hi v-ljerr-msft
Thank you for your help with developing this solution. I have updated the code slightly to cater for the fact that when a particular Tag I am searching for is at the end of the text string the code would fail because it can't find the last delimitated character ",". So I have changed the delimited character to be ". Now any tag of any length and position within the string can be found and separated out into its own column. e.g. Workload, Location, Hostname. Hopefully this code can be used by others who are trying to report against Azure resource tags.
Hostname = IF(SEARCH( "Hostname" ,'All-Azure-Data'[Data.Tags],,BLANK() ) ,( VAR textLength = SEARCH ( """", 'All-Azure-Data'[Data.Tags], SEARCH ( "Hostname", 'All-Azure-Data'[Data.Tags] ) + LEN ( "Hostname" ) + 3 ) - ( SEARCH ( "Hostname", 'All-Azure-Data'[Data.Tags] ) + LEN ( "Hostname" ) + 3 ) RETURN MID ( 'All-Azure-Data'[Data.Tags], SEARCH ( "Hostname", 'All-Azure-Data'[Data.Tags] ) + LEN ( "Hostname" ) + 3, textLength )))
Microsoft EmployeeHi Danny26,
If I understand you correctly, you should be able to use MID and FIND DAX function to create new calculate columns under Modeling tab to search for a key word in the Tags column and then place that value into a separate column in your scenario. The formula below is for your reference. :smileyhappy:
Hostname =
MID (
Table1[Tags],
FIND ( "Hostname", Table1[Tags] ) + LEN ( "Hostname" )
+ 3,
LEN ( "TestSvr01" )
)
Regards
Hi v-ljerr-msft
Thank you very much for the reply you have certainly giving me that spark I needed. I have added to the code an IF statement so if the key word is not found in the particular row e.g. the row which contains all the Azure tag information then do not perform the operation otherwise I get text in there that I don't want.
Hostname =
IF(FIND("Hostname",'Table1'[Tags],,BLANK()),
MID ( 'Table1'[Tags], FIND("Hostname",Table1'[Data.Tags],,BLANK()) + LEN ( "Hostname" ) + 3, LEN ( "TestSvr01" ) ),"")I would like to add a further bit of logic which caters for a hostname of variable length. I was going about this by doing another FIND command from the position determined by the first FIND command and locate the end position of the delimited character in this case a comma ",". Once I had that number I was going to subtract the number of characters that make up the word "Hostname" to give me the total number of characters the hostname represents. So TestSvr01 would return 9 characters and Server01 would return 8 characters. With the correct number of characters found I was going to pass it to the MID command so it only extracts the right amount of text e.g. only the hostname and no trailing characters.
I understand that you cannot pass a variable or an operation in <start_num> section of a FIND command as per FIND(<find_text>, <within_text>[, [<start_num>][, <NotFoundValue>]]) because this command doesn’t work
FIND(",",'Table1'[Tags],FIND("Hostname",'Table1'[Tags],,BLANK()),BLANK())
so I am a little bit stumped as to how to calculate the correct number characters in a hostname and pass that to a MID command and extract only the hostname so any further assistance would be greatly appreciated. Also if you know of any easier way to achieve the same result say with the Power Query command "Text.PositionOf" that would be great as well. If we can solve this last outstanding question then my reports back to management would be complete.
Thanks again!
Danny
- v-ljerr-msft
Hi Danny26,
Try the formula below to see if it works in your scenario. :smileywink:
Hostname = VAR textLength = FIND ( ",", Table1[Tags], FIND ( "Hostname", Table1[Tags] ) + LEN ( "Hostname" ) + 3 ) - ( FIND ( "Hostname", Table1[Tags] ) + LEN ( "Hostname" ) + 3 ) - 1 RETURN MID ( Table1[Tags], FIND ( "Hostname", Table1[Tags] ) + LEN ( "Hostname" ) + 3, textLength )Regards
Hi v-ljerr-msft
Thank you for the code block. When I copy it across and update the table names it doesn't strictly work straight away. For reasons which I am not quite sure about any FIND command I use in Power BI desktop (which is the current April 2017 version) doesn't work unless I include ,,BLANK() on the end otherwise I get the error "The search Text provided to the function 'FIND' could not be found in the given text' so I have amended the code as per below. So it appears that all the FIND commands work now but the MID command does not.
I am presented with the error 'An argument of function 'MID' has the wrong data type or has an invalid value' so I am assuming this is because we are trying to pass it the variable name 'textLength' as the command works when I replace that with a number typed in by myself, my understanding was you couldn't pass a variable to the MID command. I'm sure the code block works when you constructed your example so I am not sure what the difference between the two could be, do you think I changed how the code executed by adding ,, BLANK() to the end of the FIND command.
Hostname = VAR textLength = FIND ( ",", TestBatch4[Tags], FIND ( "Hostname", TestBatch4[Tags],,BLANK()) + LEN ( "Hostname" ) + 3 ,BLANK()) - ( FIND ( "Hostname", TestBatch4[Tags],,BLANK()) + LEN ( "Hostname" ) + 3 ) - 1 RETURN MID ( TestBatch4[Tags], FIND ( "Hostname", TestBatch4[Tags],,BLANK()) + LEN ( "Hostname" ) + 3, textLength )Once again thank you very much for your help and I certainly do like how this solution is being solved.
Regards
Danny