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Anonymous's avatar
Anonymous
Not applicable
4 years ago

How to sort a bar chart depending on slicer selection

Hello everyone,

 

How can i sort a bar chart depending on slicer selection?

 

I mean if i select in slicer "Sum of IDADE" i want the sort descending from the values, and if i select in slicer "Sum of ALTURA" i want the sort descending. Or if i Select All just let the sort descending from Sum of ALTURA values.

 

Is this possible?

 

Thanks.

 

 

5 Replies

  • juhui's avatar
    juhui
    Regular Visitor

    i have this problem too. do you have answer?

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi  Anonymous ,

    I created some data:

    Here are the steps you can follow:

    1. Use Enter data to create a table as a slicer.

    2. Create measure.

    Flag =
    SWITCH(
       TRUE(),
        MAX('Slicer'[ALTURA.IDADE])="Sum of IDADE",CALCULATE(SUM('Table'[Amount]),FILTER(ALL('Table'),'Table'[CA]=MAX('Table'[CA]))),
        MAX('Slicer'[ALTURA.IDADE])="Sum of ALTURA",CALCULATE(SUM('Table'[Amount]),FILTER(ALL('Table'),'Table'[CA]=MAX('Table'[CA]))),
        MAX('Slicer'[ALTURA.IDADE])="ALL",
    CALCULATE(SUM('Table'[Amount]),FILTER(ALL('Table'),'Table'[Group]="ALTURA"&&'Table'[CA]=MAX('Table'[CA]))))
    rank =
    RANKX(ALL('Table'),[Flag],,DESC)

    3. Put [Rank] on the Tooltips of the bar graph.

    4. Sort axis – [Rank] – Sort descending.

    5. Result:

    If you need pbix, please click here.

     

    Best Regards,

    Liu Yang

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

    • Anonymous's avatar
      Anonymous
      Not applicable

      Hi, 

      I can´t download the file.

    • Anonymous's avatar
      Anonymous
      Not applicable

      That's not what i pretend. 

      I want the sort descending from the values, and if i select in slicer "Sum of ALTURA" i want the sort descending depending on that value. Or if i Select All just let the sort descending from Sum of ALTURA values.