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ykannan
Helper I
Helper I

How to show Average values in Total section

I am trying to create PowerBI report with same data as in other BI tool,

In PowerBI,I have created measures like,

DO_Count = count(creo_sales[DO_ID])
 
EGPS DO Count = COUNTROWS (
    FILTER (
        creo_sales,
         CONTAINSSTRING(creo_sales[OP_GROUP_NAME], "GPS")))
 
Percent EGPS DO's = [EGPS DO Count]/[DO_Count]
 
In the percentage EGPS DO's columns, total section, I want to have Average value instaed of Total. In those above measures, I could not see Average aggregation.

 

ykannan_1-1681795028128.png

 

Other BI tool,

DO Count= =Count([Delivered Order ID])

 

EGPS DO Count=Count([Delivered Order ID];Distinct) Where(Match([Order Planning Group];"*Excelsius GPS*")) ForEach([Delivered Order ID]) In([YEAR])

 

Percent EGPS DO's = =[EGPS DO Count]/[DO Count]

 

I can do the Average in other BI tool. How can I do the same in Power BI?

 

ykannan_3-1681795414603.png

 

As per below article, Measures do not have the aggregate values below shown options,

Work with aggregates (sum, average, and so on) in Power BI - Power BI | Microsoft Learn

ykannan_5-1681795603738.png

Thanks,

Yoga

1 ACCEPTED SOLUTION
v-rzhou-msft
Community Support
Community Support

Hi @ykannan ,

 

I suggest you to use Averagex() function to create a new measure based on [Percent EGPS DO's] measure.

New Percent EGPS DO's =
AVERAGEX ( VALUES ( 'TableName'[Year] ), [Percent EGPS DO's] )

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

View solution in original post

1 REPLY 1
v-rzhou-msft
Community Support
Community Support

Hi @ykannan ,

 

I suggest you to use Averagex() function to create a new measure based on [Percent EGPS DO's] measure.

New Percent EGPS DO's =
AVERAGEX ( VALUES ( 'TableName'[Year] ), [Percent EGPS DO's] )

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

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