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I am measuring productivity and I have the units manufactured for each worker for each date, for which I create a graph that shows me the average productivity, and a letter that shows me the average of all workers.
The issue is that it is not the real value for March since it takes into account dates in which it was not worked (examples Sunday and some Saturdays)
Solved! Go to Solution.
Hi @Syndicate_Admin ,
Please try the following formula:
average productivity day =
SUM ( Sheet1[Units] ) / CALCULATE ( DISTINCTCOUNT ( Sheet1[Date] ), Sheet1[Units] <> BLANK () )
If the problem is still not resolved, please provide detailed error information or the expected result you expect. Let me know immediately, looking forward to your reply.
Best Regards,
Winniz
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @Syndicate_Admin ,
Please try the following formula:
average productivity day =
SUM ( Sheet1[Units] ) / CALCULATE ( DISTINCTCOUNT ( Sheet1[Date] ), Sheet1[Units] <> BLANK () )
If the problem is still not resolved, please provide detailed error information or the expected result you expect. Let me know immediately, looking forward to your reply.
Best Regards,
Winniz
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
I tried to create a new measurement with DISTINCTCOUNTNONULL(date) but I need you to use the date filter of the photo.
Is there a way to use a "slicer" as a filter for a measurement?
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