Forum Discussion
How Do I Calculate Project Activity Back and Forth
- 4 years ago
Hi Anonymous ,
Reaching this is more difficult. You can try the following steps.
First create an index column.
Create a calculated column to calculate the number of times the current row belongs to tech review.How many times = VAR _maxIndexOf_ProjectAndStage = MAXX ( FILTER ( 'Table', 'Table'[ProjectId] = EARLIER ( 'Table'[ProjectId] ) && [Stage_Name] = "Tech Review" ), [Index] ) VAR _maxIndexOfProject = MAXX ( FILTER ( 'Table', 'Table'[ProjectId] = EARLIER ( 'Table'[ProjectId] ) ), [Index] ) VAR _countNotTechReview = COUNTROWS ( FILTER ( 'Table', [Index] > EARLIER ( 'Table'[Index] ) && [Stage_Name] <> "Tech Review" ) ) RETURN IF ( [Stage_Name] = "Tech Review", _countNotTechReview - ( _maxIndexOfProject - _maxIndexOf_ProjectAndStage - 1 ) )
Create another column to calculate how many days the current tech review has consumed.length of XXX calendar days = VAR _start = MAXX ( FILTER ( 'Table', [ProjectId] = EARLIER ( 'Table'[ProjectId] ) && [How many times] = EARLIER ( 'Table'[How many times] ) ), [Created] ) VAR _end = MINX ( FILTER ( 'Table', [ProjectId] = EARLIER ( 'Table'[ProjectId] ) && [How many times] = EARLIER ( 'Table'[How many times] ) ), [Created] ) RETURN IF ( [Stage_Name] = "Tech Review", VALUE ( _start - _end ) + 1 )Finally, in the visual chart, seperate the maximum number of times for the current project id and average the number of days using the following formula.
average length of XXX calendar days = AVERAGEX(VALUES('Table'[length of XXX calendar days]),[length of XXX calendar days])Pbix in the end you can refer.
Best Regards
Community Support Team _ chenwu zhu
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Thank you for this. I was able to group and index all of the projects. I reposted my question with a new issue that is coming up in "how many times" column. It is under the question
"Count Column by Group and filter"
https://community.powerbi.com/t5/Desktop/Count-Column-by-Group-and-filter/m-p/2473373#M881651
Maybe you could take a look at this new issue. I think it is almost solved! Thank you again!