Forum Discussion
Hierarchies- need some help
It's hard to understand exactly what your issue is - maybe show a screenshot?
I have a table which contains a value for all my locations.
each location has a value
the locations are placed in a hierarchy and i have build a graph that drills down through the different levels
it works, but it sums or i my case averages the values
as it is averaging all the values under the hierarchy structure, it does not give the value for that location
example
l1 3.5
l2a 3
l2b 3
l2c 4
the l1 value seem to be the average of all the values rather than 3.5
hope this clarifies
Note the size o fthe location differ so an average is not really any use
- Anonymous10 years agoNot applicable
Hello docjohn
If I'm right, you want to see the numerci value on each level of your hierarchy without aggregation function, that's it?
I guess you cannot do it because drill down chart needs a aggregate value to display the item.
I think, the only way to do this (i.e : display the value belonging to the level) is to use the value concatenat with the level.
If I get you example, it will show :
Name / Value / New column
I1 / 3.5 / I1-3.5
I2a / 3 / I2a-3
I2b / 3 / I2b - 3
I2C / 4 / I2c-4
But unfortunately it going to be hard to use the new column as location. Sorry not to find a better solution. Hope it helps anyway.
Sébastien
- austinsense10 years agoImpactful Individual
I still have no idea what the issue is
- rmccallion10 years agoFrequent Visitor
If I understand your issue - I think that I'm having the same one - and if so, perhaps I can give more details which may help others understand the problem.
I am building a dashboard to monitor/analyze our current sprints and there are only two levels for the drilldown. At the highest level, I have a sum of the actual work and the estimated work broken down by iteration and then a multirow card to show the total numbers. If I then create a third value - the average - when I drilldown to the actual task level, then the average would in fact be correct and this instance, the average actual work would be 87/12. However, if no matter how I try to calculate the average at the parent (Iteration) level, it's always using the count of items at the task level. What I want to do is to divide the 87 actual hours (at the iteration level) by the number of iterations (in this case, 3). 87/3 being the number that would represent the average actual work for tasks for the entire iteration. I hope that this helps clarify the issue. Screenshots of both levels as per below:
Child Task LevelParent Iteration Level
- residentx10 years agoHelper IV
I know you've figured this out by now but you need to turn-off aggregation or set for "no aggregation" or average