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- 8 years ago
Hello,
I couldn't test 'Dense' last week so I did it today.
My Measure is TopN:=CALCULATE(MAX(Test_Rank[Data]);FILTER(Test_Rank;RANKX(Test_Rank;[Data];;;Dense)=Top_3[MaxN]))
This is my over all:
For me it looks like it is supposed.
Hello I see,
but PowerPivot is simply amazing, I think there is an OnBoard Solution.
Check out RANKX RANKX(<table>, <expression>[, <value>[, <order>[, <ties>]]])
So you could add RANKX(Test_Rank;[Data];;Dense)
I think the description in the link is well done. So this should help.
Hi Floriankx,
RANKX(Test_Rank;[Data];;Dense)
Not working in my case. please try to use once in your side.
Maybe some important thing u get
Regards,
NICK
- Floriankx8 years agoSolution Sage
Hello,
I couldn't test 'Dense' last week so I did it today.
My Measure is TopN:=CALCULATE(MAX(Test_Rank[Data]);FILTER(Test_Rank;RANKX(Test_Rank;[Data];;;Dense)=Top_3[MaxN]))
This is my over all:
For me it looks like it is supposed.
- Naveennegi1198 years agoHelper III
Hi all,
help to out this guyz.
Regards,
NICK
- Naveennegi1198 years agoHelper III
Hi Floriankx,
I was gone to trip, so could not read your msg.
Thanks for every help you did it in past few days.
Regards,
NICK