Forum Discussion
Help with getting the maximum value from calculated table containing measure column
- 6 years ago
Hi miguelsus2000 ,
Miguel, I tested your sample data. Maybe the following formula can help you. For why you get the sum value, I think it is caused that my sample is too simple. It is filtered by other columns in your actual data.
MAXX = MAXX ( SUMMARIZE ( FILTER ( ALLSELECTED ( 'LoRaBlePayload (2)' ), 'LoRaBlePayload (2)'[Content.BeaconIdentifier] IN FILTERS ( 'LoRaBlePayload (2)'[Content.BeaconIdentifier] ) ), 'LoRaBlePayload (2)'[Content.BeaconIdentifier], 'LoRaBlePayload (2)'[PartitionKey], "New", [Count per BID] ), [New] )Best Regards,
Xue Ding
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I forgot to add the table, but the Count per BID is a caluclated measure which MAX doesn't like.
where does Count per BID field come from? Is it coming from same table like 'LoRaBlePayload (2)?
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- miguelsus20006 years agoHelper III
Thie Count per Bid is below:
Count per BID =CALCULATE(COUNTA('LoRaBlePayload (2)'[Content.BeaconIdentifier]),FILTER(ALLSELECTED('LoRaBlePayload (2)'[Content.Rssi]),ISONORAFTER('LoRaBlePayload (2)'[Content.Rssi], MAX('LoRaBlePayload (2)'[Content.Rssi]), DESC)))This tells me how many readings i've received for each partition key for each content.beaconidentifier. Now, i only want the max for each group of content.beaconidentifier,t hen show all 3 columns for that max. Eg. from the calculated table above, i want to show:Content.beaconidentifier Max Count Partitionkey0000-1040l 32 7b....580000-1040O 32 7b....580000-10413 43 7b....58if i dont need to use Count per Bid, it's ok, but needed a way to verify the maxAny ideas?- miguelsus20006 years agoHelper III
Hi... I still have not been able to figure it out, i can use any help you guys can get me. Thank you..M
- v-xuding-msft6 years agoCommunity Support
Hi miguelsus2000 ,
You could try to use the function of MAXX.
Measure = CALCULATE ( MAXX ( 'LoRaBlePayload (2)', [Count per BID] ), ALLEXCEPT ( 'LoRaBlePayload (2)', 'LoRaBlePayload (2)'[Content.BeaconIdentifier] ) )Best Regards,
Xue Ding
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.