Forum Discussion
Group numbers
- Anonymous4 years ago
Hi jeroend ,
Here are the steps you can follow:
Graphs to visualize how many invoices are above the value 50.000”:
1. Create measure.
Flag = IF( MAX('Table'[Value]) >500000,1,0)2. Place [Flag] in Filters, set is=1, apply filter.
3. Result:
Only values greater than 500,000 are displayed
How many invoices are above a certain amount and this in % of total invoices:
1. Create measure.
% of total invoices = var _over_allcount=COUNTX(FILTER(ALL('Table'), 'Table'[Value]> 500000),[Number]) var _totalinvoices=COUNTX('Table','Table'[Number]) return DIVIDE(_over_allcount,_totalinvoices)2. Result:
How many invoices of the have a po number in the summarry column and this in relation of the total invoices:
1. Create measure.
IF_ponumber = var _mid=MID(MAX('Table'[Summary]),5,1) return IF( _mid <> "-",1,0)summarry% = var _countponumber=COUNTX(FILTER(ALL('Table'),[IF_ponumber]=1),[Number]) var _countall=COUNTX('Table','Table'[Number]) return DIVIDE(_countponumber,_countall)2. Result.
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
Hi jeroend ,
Here are the steps you can follow:
Graphs to visualize how many invoices are above the value 50.000”:
1. Create measure.
Flag =
IF(
MAX('Table'[Value]) >500000,1,0)
2. Place [Flag] in Filters, set is=1, apply filter.
3. Result:
Only values greater than 500,000 are displayed
How many invoices are above a certain amount and this in % of total invoices:
1. Create measure.
% of total invoices =
var _over_allcount=COUNTX(FILTER(ALL('Table'),
'Table'[Value]> 500000),[Number])
var _totalinvoices=COUNTX('Table','Table'[Number])
return
DIVIDE(_over_allcount,_totalinvoices)
2. Result:
How many invoices of the have a po number in the summarry column and this in relation of the total invoices:
1. Create measure.
IF_ponumber =
var _mid=MID(MAX('Table'[Summary]),5,1)
return
IF(
_mid <> "-",1,0)summarry% =
var _countponumber=COUNTX(FILTER(ALL('Table'),[IF_ponumber]=1),[Number])
var _countall=COUNTX('Table','Table'[Number])
return
DIVIDE(_countponumber,_countall)
2. Result.
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly