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Rdarshana's avatar
Rdarshana
Helper II
2 years ago
Solved

Formula Explanation

Hi,
Can someone explain to me what this formula does - 

ID Count = COUNTROWS(DISTINCT(SELECTCOLUMNS('Fact 1', "ID Column", RELATED('Dim 2 '[ID Column]))))

From what I understand, we are picking distinct values of the ID attribute from Dim 2 table, but only those relevant to having data in the fact 1 table). Is this correct?
 

 

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  • Anonymous's avatar
    Anonymous
    2 years ago

    Hi Rdarshana ,

    I created a sample pbix file(see the attachment), you can find the details in it. And for below formula, it will return the count of ID in the table 'Fact 1' which ID also in the dimenison table 'Dim 2'. However, it will also include the IDs in 'Fact 1' table which not exist in the table 'Dim 2' as blank values. All these blank values count as 1. Please check the below screenshot:

    ID Count = COUNTROWS(DISTINCT(SELECTCOLUMNS('Fact 1', "ID Column", RELATED('Dim 2 '[ID Column]))))

    So you can update the forumula as below to get the correct count of ids.

    ID Count_new =
COUNTROWS (
    FILTER (
        DISTINCT (
            SELECTCOLUMNS ( 'Fact 1', "ID Column", RELATED ( 'Dim 2'[Dim ID] ) )
        ),
        [ID Column] <> BLANK ()
    )
)

    Best Regards

5 Replies

  • MattAllington's avatar
    MattAllington
    Community Champion
    2 years ago

    That's what it looks like to me, but it also looks overly complex. Assuming Dim ID in dim 2 is the primary key, this should work. 

     

    ID Count = calculate(countrows('Dim 2 '),'Fact 1')

Or this next version is a bit easier to understand 

Calculate(countrows('Dim 2'),crossfilter(fact1[key],DIM2[key],BOTH))

     

    They both do the same thing; force the fact table to filter the Dim table based on the existence of matching data in the fact table. 

  • Rdarshana's avatar
    Rdarshana
    Helper II
    2 years ago

    Thanks Matt.
    The Dim ID in this screenshot above is not the primary key, but another attribute (ID). 
    I will need to test the other calcs to see if that works.

    • MattAllington's avatar
      MattAllington
      Community Champion
      2 years ago

      if it's not the primary key, just insert the VALUES function inside the countrows function

      COUNTROWS(VALUES(table[column]))

  • Anonymous's avatar
    Anonymous
    Not applicable
    2 years ago

    Hi Rdarshana ,

    I created a sample pbix file(see the attachment), you can find the details in it. And for below formula, it will return the count of ID in the table 'Fact 1' which ID also in the dimenison table 'Dim 2'. However, it will also include the IDs in 'Fact 1' table which not exist in the table 'Dim 2' as blank values. All these blank values count as 1. Please check the below screenshot:

    ID Count = COUNTROWS(DISTINCT(SELECTCOLUMNS('Fact 1', "ID Column", RELATED('Dim 2 '[ID Column]))))

    So you can update the forumula as below to get the correct count of ids.

    ID Count_new =
COUNTROWS (
    FILTER (
        DISTINCT (
            SELECTCOLUMNS ( 'Fact 1', "ID Column", RELATED ( 'Dim 2'[Dim ID] ) )
        ),
        [ID Column] <> BLANK ()
    )
)

    Best Regards