Supplies are limited. Contact info@espc.tech right away to save your spot before the conference sells out.
Get your discountScore big with last-minute savings on the final tickets to FabCon Vienna. Secure your discount
I have a list of serial numbers and the date in which they were serviced.
I also did a formula that is identifying the first repair and the duplicate repairs.
But what I would need now is to know the date in which the prior repair came in
Serial Date Serviced Repeat?
A 01/01/2019 First Repair
B 01/01/2019 First Repair
A 01/05/2019 Duplicate Repair
A 01/07/2019 Duplicate Repair
The expected outcome would be like this
Serial Date Serviced Repeat? Prior Repair Date
A 01/01/2019 First Repair -
B 01/01/2019 First Repair -
A 01/05/2019 Duplicate Repair 01/01/2019
A 01/07/2019 Duplicate Repair 01/05/2019
Would appreicate your insights on this! I have already searched plenty but could not find something that fits the situation.
Thank you!
Solved! Go to Solution.
Hi @Anonymous
Try this:
Prior Repair Date = CALCULATE ( MAX ( Table1[Date Serviced] ), Table1[Date Serviced] < EARLIER ( Table1[Date Serviced] ), ALLEXCEPT ( Table1, Table1[Serial] ) )
Please mark the question solved when we get to the solution and consider kudoing if posts are helpful.
Cheers
Hi @Anonymous
Try this:
Prior Repair Date = CALCULATE ( MAX ( Table1[Date Serviced] ), Table1[Date Serviced] < EARLIER ( Table1[Date Serviced] ), ALLEXCEPT ( Table1, Table1[Serial] ) )
Please mark the question solved when we get to the solution and consider kudoing if posts are helpful.
Cheers
User | Count |
---|---|
64 | |
59 | |
47 | |
33 | |
32 |
User | Count |
---|---|
84 | |
74 | |
54 | |
50 | |
44 |