Forum Discussion
Helper IFinding the maximum temperature recorded for a day
Hi all,
I have a dataset that contains timestamps and temperature. I am interested in finding the maximum temperature recorded for each day for last week. The data recorded in about every 2 mins. The relative date slicers are not applicable as it does not help if the dataset is not refreshed.
Please help me on how to do this with DAX. Thanks.
Regards,
Vipul Toshniwal
PS
Hi VipulToshniwal ,
You can try this measure to achieve maximum temperature of a day:
Max_temperature of current day =
VAR _curr =
SELECTEDVALUE ( 'Table'[timestamp_IST] )
RETURN
CALCULATE (
MAX ( 'Table'[Temperature] ),
FILTER (
ALL ( 'Table' ),
YEAR ( 'Table'[timestamp_IST] ) = YEAR ( _curr )
&& MONTH ( 'Table'[timestamp_IST] ) = MONTH ( _curr )
&& DAY ( 'Table'[timestamp_IST] ) = DAY ( _curr )
)
)
You will get the result like this:
Here is the demo, please try it:
Best Regards,
Yingjie Li
If this post helps then please consider Accept it as the solution to help the other members find it more quickly.
2 Replies
- amitchandak
Super User
Create a date field
Date = Table[Datetime].date
And then you can display is against each date
Prefer using a date dimension
In case you want to take max and sum refer
https://community.powerbi.com/t5/Desktop/SUM-of-AVERAGE/td-p/197013
Also refer :https://community.powerbi.com/t5/Desktop/highest-value-by-category/td-p/428758
In any case you need to create a date column
Appreciate your Kudos.
v-yingjlCommunity Support
Hi VipulToshniwal ,
You can try this measure to achieve maximum temperature of a day:
Max_temperature of current day =
VAR _curr =
SELECTEDVALUE ( 'Table'[timestamp_IST] )
RETURN
CALCULATE (
MAX ( 'Table'[Temperature] ),
FILTER (
ALL ( 'Table' ),
YEAR ( 'Table'[timestamp_IST] ) = YEAR ( _curr )
&& MONTH ( 'Table'[timestamp_IST] ) = MONTH ( _curr )
&& DAY ( 'Table'[timestamp_IST] ) = DAY ( _curr )
)
)
You will get the result like this:
Here is the demo, please try it:
Best Regards,
Yingjie Li
If this post helps then please consider Accept it as the solution to help the other members find it more quickly.
