Forum Discussion
Filtered Selection and All selected
- 1 year ago
M_SBS_6 ,
To achieve the desired behavior where the logic returns the percentage value based on the individual filter selection and the total when all FYs are selected, you can modify your DAX formula to check if all FYs are selected and then calculate the total accordingly. Here is an updated version of your DAX formula:
DAX
New_apps =
IF(
ISFILTERED(test[dateFY]),
SWITCH(
TRUE(),
MAX(test[dateFY]) = "21/22", DIVIDE(test[new_apps 21/22], test_one[all 21/22]),
MAX(test[dateFY]) = "22/23", DIVIDE(test[new_apps 22/23], test_one[all 22/23]),In this formula:
ISFILTERED(test[dateFY]) checks if the dateFY column is filtered.
- Anonymous1 year ago
Hi,
Thanks for the solution bhanu_gautam offered, and i want to offer some more information for user to refer to.
hello M_SBS_6 , you can try the following measure.
New_apps = IF ( ISFILTERED ( test[dateFY] ), IF ( SELECTEDVALUE ( test[dateFY] ) = "21/22", DIVIDE ( test[new_apps 21/22], test_one[all 21/22] ), IF ( SELECTEDVALUE ( test[dateFY] ) = "22/23", DIVIDE ( test[new_apps 22/23], test_one[all 22/23] ), IF ( SELECTEDVALUE ( test[dateFY] ) = "23/24", DIVIDE ( test[new_apps 23/24], test_one[all 23/24] ) ) ) ), Test[new_apps_all] / test_one[all] )Best Regards!
Yolo Zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi,
Thanks for the solution bhanu_gautam offered, and i want to offer some more information for user to refer to.
hello M_SBS_6 , you can try the following measure.
New_apps =
IF (
ISFILTERED ( test[dateFY] ),
IF (
SELECTEDVALUE ( test[dateFY] ) = "21/22",
DIVIDE ( test[new_apps 21/22], test_one[all 21/22] ),
IF (
SELECTEDVALUE ( test[dateFY] ) = "22/23",
DIVIDE ( test[new_apps 22/23], test_one[all 22/23] ),
IF (
SELECTEDVALUE ( test[dateFY] ) = "23/24",
DIVIDE ( test[new_apps 23/24], test_one[all 23/24] )
)
)
),
Test[new_apps_all] / test_one[all]
)
Best Regards!
Yolo Zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.