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Hi all
There is a list of 4000 dublicated ABC entries assigned to multiple owners. some have given feedback, others not. These ABC entries should get a status by the owner "open", "reviewed" or "not possible". I would like to map all "open" with "reviewed" items and would like to filter for all ABC entries which occur in both lists. Any idea how to do in DAX to display this in a table ?
thanks all
Solved! Go to Solution.
HI @mansch,
You can try to use the following calculated column formula to check the different row count based on the current 'field 1'', 'field 2' group to setting record flags:
Flag =
VAR check =
CALCULATETABLE (
COUNTROWS ( VALUES ( T[3] ) ),
FILTER (
T,
T[1] = EARLIER ( T[1] )
&& OR ( T[2] = EARLIER ( T[2] ), T[2] = "reviewed" )
)
)
RETURN
IF ( check > 1, "Y", "N" )
Regards,
Xiaoxin Sheng
HI @mansch,
You can try to use the following calculated column formula to check the different row count based on the current 'field 1'', 'field 2' group to setting record flags:
Flag =
VAR check =
CALCULATETABLE (
COUNTROWS ( VALUES ( T[3] ) ),
FILTER (
T,
T[1] = EARLIER ( T[1] )
&& OR ( T[2] = EARLIER ( T[2] ), T[2] = "reviewed" )
)
)
RETURN
IF ( check > 1, "Y", "N" )
Regards,
Xiaoxin Sheng
1 | 2 | 3
AA | open |
BB | open |
CC | reviewed |
DD | reviewed | XX
AA | reviewed | ZZ
BB | open
CC | open
DD | reviewed | YY
Each row is assigned to a different owner. [the empty row is only there for better visibility]
I am aiming to see
1. "reviewed" with a different value in "3"
- DD has a different value
2. all "1" with different value in "3"
- CC and DD have different values
not sure why the second result is CC and DD. I think should be AA and CC
pls try this
@mansch
not sure why the second result is CC and DD. I think should be AA and CC
Column 2 =
VAR check=maxx(FILTER('Table','Table'[Column1]=EARLIER('Table'[Column1])&&'Table'[Column2]<>EARLIER('Table'[Column2])),'Table'[Column2])
return if(check<>"","Yes")
Proud to be a Super User!
could you pls provide the sample data and expected output?
Proud to be a Super User!
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