Forum Discussion
Fill down by group
- 6 years ago
Hi Kpham ,
I created the test data.
Sort the two columns first, then group them and fill them down.
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WSlTSUVKK1UFjGGJhgRlJWBlGWFhgRjJWhjFWoVgA", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t, Column2 = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"Column1", type text}, {"Column2", Int64.Type}}), #"Sorted Rows" = Table.Sort(#"Changed Type",{{"Column1", Order.Ascending}, {"Column2", Order.Descending}}), #"Group" = Table.Group(#"Sorted Rows", {"Column1"}, {{"All_Rows", each Table.FillDown(_,{"Column2"}), type table}}), #"Expanded All_Rows" = Table.ExpandTableColumn(Group, "All_Rows", {"Column1", "Column2"}, {"All_Rows.Column1", "All_Rows.Column2"}) in #"Expanded All_Rows"Best Regards,
Liang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Kpham
Sort Ascending on Delivery
Sort Decending on Refernce Doc.
Fill donw on Refernce Doc.
________________________
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unfortunately some delivery doesnt have a reference doc. So i will create not existing combinations
- V-lianl-msft6 years agoCommunity Support
Hi Kpham ,
I created the test data.
Sort the two columns first, then group them and fill them down.
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WSlTSUVKK1UFjGGJhgRlJWBlGWFhgRjJWhjFWoVgA", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t, Column2 = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"Column1", type text}, {"Column2", Int64.Type}}), #"Sorted Rows" = Table.Sort(#"Changed Type",{{"Column1", Order.Ascending}, {"Column2", Order.Descending}}), #"Group" = Table.Group(#"Sorted Rows", {"Column1"}, {{"All_Rows", each Table.FillDown(_,{"Column2"}), type table}}), #"Expanded All_Rows" = Table.ExpandTableColumn(Group, "All_Rows", {"Column1", "Column2"}, {"All_Rows.Column1", "All_Rows.Column2"}) in #"Expanded All_Rows"Best Regards,
Liang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.