Forum Discussion
Anonymous
5 years agoNot applicable
Exact Age
Hello,
I'm trying to calculate the age of a personn at a date X. I have two columns, one is his birthday date and the other a date X . I would like to know the exact age of the personn at this day. For exemple if it's birthday is the 10/05/2018 and the X date is 11/05/2021, I would like to have 3. But if my X date is 09/05/2021 I would like to have 2.
I tried a datediff but after it gives me a number of day between those two dates and I don't know how to convert it to have the exact year cause of leap years...
if someone have a solution it would be very usefull.
Thank you
Have a nice day
Best regards
Anonymous
Add the Age column as follows:AGE = INT( DIVIDE( [DATE X]-[DOB], 365.25 ) )
2 Replies
- FowmySuper User
Anonymous
Add the Age column as follows:AGE = INT( DIVIDE( [DATE X]-[DOB], 365.25 ) )- AnonymousNot applicable
Thanks!