Forum Discussion
Error ordering Sizes
- Anonymous4 years ago
Hi Syndicate_Admin ,
According to your statement, I think you want to sort [TallaO] column by [OrdenTalla]. However, I find there are multiple duplicates sort numbers in [OrdenTalla] for different [TallaO].
For example:
TallaO = 10, OrdenTalla = 8
TallaO = 3x, OrdenTalla = 8
This will make Power BI confused which one should be sorted in 8.
So you will get error when you sort [TallaO] column by [OrdenTalla]. I can reproduce your issue in my test.
I find that there are multiple sort number when TallaO equal to S.
TallaO = S, OrdenTalla = 1
TallaO = S, OrdenTalla = 2
This will casue error as well. Due to this situation, we can not add another new sort to achieve your goal.
So I suggest you to add [OrdenTalla] in Matrix column field in top level.
Best Regards,
Rico ZhouIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Graccias me sale el error Column 'new OrdenTalla' cannot be found or may not be used in this expression.
I understand that if the Size number is not in the matrix it should be increased or create a larger number?
Hi Syndicate_Admin ,
According to your statement, I think you want to sort [TallaO] column by [OrdenTalla]. However, I find there are multiple duplicates sort numbers in [OrdenTalla] for different [TallaO].
For example:
TallaO = 10, OrdenTalla = 8
TallaO = 3x, OrdenTalla = 8
This will make Power BI confused which one should be sorted in 8.
So you will get error when you sort [TallaO] column by [OrdenTalla]. I can reproduce your issue in my test.
I find that there are multiple sort number when TallaO equal to S.
TallaO = S, OrdenTalla = 1
TallaO = S, OrdenTalla = 2
This will casue error as well. Due to this situation, we can not add another new sort to achieve your goal.
So I suggest you to add [OrdenTalla] in Matrix column field in top level.
Best Regards,
Rico Zhou
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.