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Anonymous's avatar
Anonymous
Not applicable
7 years ago
Solved

Efficency calculation

Hello, I have data, "total time it took to create the part"(time) and "working mins" (Whole Number). Is here a way to divide one into the other. This data would then be used to provide a percentag...
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  • v-cherch-msft's avatar
    v-cherch-msft
    7 years ago

    Hi Anonymous 

    Create a measure like below.Then drag the date column and the measure to a table visual.

    Measure =
DIVIDE (
    CALCULATE ( SUM ( Table1[Time_Second] ) ),
    CALCULATE ( MAX ( Table1[Working-Second] ) )
)

    Regards,

v-cherch-msft's avatar
v-cherch-msft
Microsoft Employee
7 years ago

Hi Anonymous 

You may convent them to seconds columns.Then use the seconds columns to get the percent as requested.

Time_second =
HOUR ( [Time it took to create the part] ) * 60 * 60
    + MINUTE ( [Time it took to create the part] ) * 60
    + SECOND ( [Time it took to create the part] )

Working_second = Table2[Working mins]*60

Regards,

  • Anonymous's avatar
    Anonymous
    Not applicable
    7 years ago

    Thanks v-cherch-msft for your help.

     

    Im am now having an issue with the division

     

     

    if i divide Time_Second into Working_Second in a measure it will sum all of the working mins

    eg Sum of Thursday working seconds = 172 +172 +171 + 80 + 141 +415 = 1,151

    but it also totals all the working seconds 32400 x 6 = 194,400

     

    Is there a way to divide it by a single 32400

    (I intend to create report visualisation by day, week month etc so cant select lowest number etc


    • v-cherch-msft's avatar
      v-cherch-msft
      Microsoft Employee
      7 years ago

      Hi Anonymous 

      You may create a measure with MAX function to get it.If it is not your case,please share some sample data and expected output which would be helpful to provide an accurate solution.

      Measure =
DIVIDE ( MAX ( [Working_second] ), SUM ( [Time_Second] ) )

      How to Get Your Question Answered Quickly

      Regards,

       

      • Anonymous's avatar
        Anonymous
        Not applicable
        7 years ago

        Apologies v-cherch-msft 

        For context;

        We have a factory machine that cuts throughout the day.  I wanted to add to the total cutting time together and then divide by the time in the workers shift in order to get the machine utilisation.

         

        on the 16th of april Tuesday i have 8 results

        1095 + 183 + 185 + 935 + 977 + 1072 + 1078 + 189 =‬ 5,714 (total seconds of machine in use)

        The total working seconds for that day would be 32400

         

        I had intended of calculating the machine usage by dividing the total seconds the machine is in use by the total working seconds in a workers shift ( 5,714/32,400 )  which would be 17.63%

        FYI on fridays we have different working hours 

        Thanks