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M_SBS_6
Helper V
Helper V

Earliest Date column split by ID

Hi, 

I have a table of which I have 3 rows of data.

 

ID. Name. Date

12. Ian B. 29/03/2023

12. Ian B. 17/12/2018   

12. Ian B. 15/04/2019

13. Kevin A 01/03/2022

13. Kevin A 02/02/2024

 

What I'd like for those 3 rows is to have another column which just populates the earliest date out of all values for that ID and Name. So I'd like my table to output like below

 

ID. Name. Date. EarliestDate

12. Ian B. 29/03/2023. 17/12/2018

12. Ian B. 17/12/2018 17/12/2018

12. Ian B. 15/04/2019. 17/12/2018

13. Kevin A 01/03/2022. 01/03/2022

13. Kevin A 02/02/2024. 01/03/2022

1 ACCEPTED SOLUTION
parry2k
Super User
Super User

@M_SBS_6 add new column using following DAX expression:

 

Earliest Date = 
CALCULATE ( 
    FIRSTDATE ( TestTable[Date] ), 
    ALLEXCEPT ( TestTable, TestTable[Id], TestTable[Name] ) 
) 


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View solution in original post

1 REPLY 1
parry2k
Super User
Super User

@M_SBS_6 add new column using following DAX expression:

 

Earliest Date = 
CALCULATE ( 
    FIRSTDATE ( TestTable[Date] ), 
    ALLEXCEPT ( TestTable, TestTable[Id], TestTable[Name] ) 
) 


Subscribe to the @PowerBIHowTo YT channel for an upcoming video on List and Record functions in Power Query!!

Learn Power BI and Fabric - subscribe to our YT channel - Click here: @PowerBIHowTo

If my solution proved useful, I'd be delighted to receive Kudos. When you put effort into asking a question, it's equally thoughtful to acknowledge and give Kudos to the individual who helped you solve the problem. It's a small gesture that shows appreciation and encouragement! ❤


Did I answer your question? Mark my post as a solution. Proud to be a Super User! Appreciate your Kudos 🙂
Feel free to email me with any of your BI needs.

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