Forum Discussion
Dynamically changing name ofthe column header
- Anonymous6 years ago
Hi dia612,
It means you can create a list with the column names you wanted, then you can invoke them in your query table with 'renamecolumns' function to dynamic rename current column names:
Columnname stored a list of column names strings
let Source = {"id","name","desc"} in SourceQuery table invokes above list to rename fields:
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMjRU0lEyMgISxsZKsbEA", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t, Column2 = _t, Column3 = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"Column1", Int64.Type}, {"Column2", Int64.Type}, {"Column3", Int64.Type}}), #"Renamed Columns" = Table.RenameColumns(#"Changed Type",List.Zip({Table.ColumnNames(#"Changed Type"),ColumnNames})) in #"Renamed Columns"Regards,
Xiaoxin Sheng
Hello Anonymous ,
Thankyou for taking time for replying.
I did not understand your suggestion clearly
"You can try to create a list with column names and invoke it in query table steps to dynamic rename your columns on the query editor side"
Could you please explain it with example
Hi dia612,
It means you can create a list with the column names you wanted, then you can invoke them in your query table with 'renamecolumns' function to dynamic rename current column names:
Columnname stored a list of column names strings
let
Source = {"id","name","desc"}
in
Source
Query table invokes above list to rename fields:
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMjRU0lEyMgISxsZKsbEA", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t, Column2 = _t, Column3 = _t]),
#"Changed Type" = Table.TransformColumnTypes(Source,{{"Column1", Int64.Type}, {"Column2", Int64.Type}, {"Column3", Int64.Type}}),
#"Renamed Columns" = Table.RenameColumns(#"Changed Type",List.Zip({Table.ColumnNames(#"Changed Type"),ColumnNames}))
in
#"Renamed Columns"
Regards,
Xiaoxin Sheng