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tracytran91's avatar
tracytran91
Helper III
5 years ago
Solved

Dynamic % Growth based on selected date slicer

Hi Folks,    I would like to calculate the growth percentage (%) based on selected date slicer.    Any help is high appreciated.  Thank you in advance.   
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  • v-yingjl's avatar
    v-yingjl
    5 years ago

    Hi tracytran91 ,

    Suppose you are comparing the past 3 months with the current month, you can create a measure like this:

    Growth% = 
VAR _mindate =
    CALCULATE ( MIN ( 'Table'[Date] ), ALLSELECTED ( 'Table'[Date] ) )
VAR _maxdate =
    CALCULATE ( MAX ( 'Table'[Date] ), ALLSELECTED ( 'Table'[Date] ) )
VAR last3month =
    CALCULATE (
        SUM ( 'Table'[value] ),
        FILTER (
            ALL ( 'Table' ),
            'Table'[Date] >= _mindate
                && 'Table'[Date] <= _maxdate
        )
    )
VAR currentmonth =
    CALCULATE (
        SUM ( 'Table'[value] ),
        FILTER (
            ALL ( 'Table' ),
            YEAR ( 'Table'[Date] ) = YEAR ( TODAY () )
                && MONTH ( 'Table'[Date] ) = MONTH ( TODAY () )
        )
    )
RETURN
    DIVIDE ( currentmonth - last3month, last3month )

    Attached a sample file in the below, hopes to help you.

     

    Best Regards,
    Community Support Team _ Yingjie Li
    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

v-yingjl's avatar
v-yingjl
Community Support
5 years ago

Hi tracytran91 ,

You can create a date table based on your source table and use it as a slicer:

Date = DISTINCT('Table'[Date])

Create a measure like this to calculate growth%:

Growth% =
VAR _selectdatevalue =
    CALCULATE (
        SUM ( 'Table'[value] ),
        FILTER ( ALL ( 'Table' ), 'Table'[Date] = SELECTEDVALUE ( 'Date'[Date] ) )
    )
RETURN
    DIVIDE ( SUM ( 'Table'[value] ) - _selectdatevalue, SUM ( 'Table'[value] ) )

Attached a sample file in the below, hopes to help you.

 

Best Regards,
Community Support Team _ Yingjie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.