Dynamic Filter of Same Column

Anonymous , in case you have date , you can use time intelligence with date calendar

Last QTD Sales = CALCULATE(SUM(Sales[Sales Amount]),DATESQTD(dateadd('Date'[Date],-1,QUARTER)))

Last complete QTD Sales = CALCULATE(SUM(Sales[Sales Amount]),DATESQTD( ENDOFQUARTER(dateadd('Date'[Date],-1,QUARTER))))
Last to last QTD Sales = CALCULATE(SUM(Sales[Sales Amount]),DATESQTD(dateadd('Date'[Date],-2,QUARTER)))
Next QTD Sales = CALCULATE(SUM(Sales[Sales Amount]),DATESQTD(dateadd('Date'[Date],1,QUARTER)))
Last year same QTD Sales = CALCULATE(SUM(Sales[Sales Amount]),DATESQTD(dateadd('Date'[Date],-1,Year)))
Last year same QTD Sales = CALCULATE(SUM(Sales[Sales Amount]),DATESQTD(ENDOFQUARTER(dateadd('Date'[Date],-1,Year))))
trailing QTR = CALCULATE(SUM(Sales[Sales Amount]),dateadd('Date'[Date],-1,QUARTER))

In case you do not have date - you can use qtr Rank // here date can be qtr table. But have it separate

Qtr Rank = RANKX(all('Date'),'Date'[Qtr Start date],,ASC,Dense)
This Qtr = CALCULATE(sum('order'[Qty]), FILTER(ALL('Date'),'Date'[Qtr Rank]=max('Date'[Qtr Rank])))
Last Qtr = CALCULATE(sum('order'[Qty]), FILTER(ALL('Date'),'Date'[Qtr Rank]=max('Date'[Qtr Rank])-1))
Last year Qtr = CALCULATE(sum('order'[Qty]), FILTER(ALL('Date'),'Date'[Qtr Rank]=(max('Date'[Qtr Rank]) -4)))

Power BI — QTD
https://medium.com/@amitchandak.1978/power-bi-qtd-questions-time-intelligence-2-5-d842063da839

To get the best of the time intelligence function. Make sure you have a date calendar and it has been marked as the date in model view. Also, join it with the date column of your fact/s. Refer :
https://radacad.com/creating-calendar-table-in-power-bi-using-dax-functions
https://www.archerpoint.com/blog/Posts/creating-date-table-power-bi
https://www.sqlbi.com/articles/creating-a-simple-date-table-in-dax/

See if my webinar on Time Intelligence can help: https://community.powerbi.com/t5/Webinars-and-Video-Gallery/PowerBI-Time-Intelligence-Calendar-WTD-YTD-LYTD-Week-Over-Week/m-p/1051626#M184


Appreciate your Kudos.