Forum Discussion
Duplicate to null and date to integer
Hi Nick2,
Have you solved your problem?
If you have solved, please always accept the replies making sense as solution to your question so that people who may have the same question can get the solution directly.
If you still need help, please feel free to ask.
Best Regards,
Cherry
Hi v-piga-msft,
tahnks for the quick answer, I'm sorry it took me so long to reply. Sadly your answer doesn't quit fix the problem, which is my fault as I wasn't precise enough. My Data looks like this:
| Date | Space |
| 11.06.2018 | A |
| 12.06.2018 | B |
| 13.06.2018 | A |
| 13.06.2018 | A+C |
| 14.06.2018 | B |
| 14.06.2018 | C |
| 15.06.2018 | C |
| 16.06.2018 | |
| 17.06.2018 | A |
| 17.06.2018 | B |
| 17.06.2018 | C |
Now there are always three rooms available (A,B,C) but not always booked and I need to know how booked we actually are. My idea was to find this out, by replacing the date with a 3, the letter with a 1, take the sums and divide the values. This obviously means, that:
1. I need to remove the dates that are more often named then one (two or three times, I misused the word duplicate, sry!) but without deleting them as I need the information from the other column. Which is why I wanted to transform them into null values.
2. change the remaining date values to 3 (as in reallity those are way more, without addressing all of them single handly)
I hope this clarifys the issue, again I'm sorry if I wasn't precise enough and I hope you'll still be able to help out.
greetings, Nick