Dividing a measure by the value of the measure where Rank =1

[Anonymous]

Hi,

I have two measures, a "Rank" and the "Measure".  I need to divide all "Measure" by the "Measure" value where Rank =1.

This looks so easy but I can't get it to work!  any ideas greatly appreciated.  The "Desired" column is what I am trying to create.

Rank	Measure	Desired
1	12000	1
2	10000	0.833333
3	8000	0.666667
4	5000	0.416667

[d_gosbell · Accepted solution]

To do a ranking you must be doing it over some column which is not visible in your sample data. So in the example below I've used a placeholder column called [Item] you will need to replace the reference to 'Table'[Item] with the reference to the actual column you are ranking over. 

Once you do this a pattern like the following should work:

Desired = 
var _rank1Measure = CALCULATE([Measure], FILTER(ALL('Table'[Item]),[Rank] = 1))
return DIVIDE([Measure], _rank1Measure)

[v-juanli-msft · Accepted solution]

Hi @Anonymous 

Create measures

Measure = SUM('Table'[value])

rank = RANKX(ALLSELECTED('Table'),[Measure],,DESC,Dense)

rank1 = CALCULATE([Measure],FILTER(ALLSELECTED('Table'),'Table'[rank]=1))

%1 = [Measure]/[rank1]

Best Regards
Maggie

Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[d_gosbell · Accepted solution]

To do a ranking you must be doing it over some column which is not visible in your sample data. So in the example below I've used a placeholder column called [Item] you will need to replace the reference to 'Table'[Item] with the reference to the actual column you are ranking over. 

Once you do this a pattern like the following should work:

Desired = 
var _rank1Measure = CALCULATE([Measure], FILTER(ALL('Table'[Item]),[Rank] = 1))
return DIVIDE([Measure], _rank1Measure)

[Anonymous]

Superb, thanks this works.  This had really foxed me.

@mwegener - thanks I created the measures as you suggested but the slight issue was that within my data are multiple rows for the same entity and the top rank amount was not at the highest level

@d_gosbell - but when I added your additional measure it worked, thanks so much for your time, greatly appreciated

[mwegener]

Hi @Anonymous ,

try this

Measure =
VAR Rank1 =
    CALCULATE (
        SUM ( 'Table'[Measure] ),
        FILTER ( ALL ( 'Table' ), 'Table'[Rank] = 1 )
    )
RETURN
    DIVIDE ( SUM ( 'Table'[Measure] ), Rank1 )

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