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Dunner2020
Post Prodigy
Post Prodigy

Distinctcount on two columns

Hi there,

 

I got two columns in a table: id and date. I want to perform distinctcount on both columns. Is there any way of performing distinctcount on two columns?

 

 

1 ACCEPTED SOLUTION
jdbuchanan71
Super User
Super User

@Dunner2020 

If you want the measure to respect other filters you can use something like this.

 

Count Combinations =
COUNTROWS ( SUMMARIZE ( YourTable, YourTable[id], YourTable[date] ) )

 

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2 REPLIES 2
jdbuchanan71
Super User
Super User

@Dunner2020 

If you want the measure to respect other filters you can use something like this.

 

Count Combinations =
COUNTROWS ( SUMMARIZE ( YourTable, YourTable[id], YourTable[date] ) )

 

selimovd
Super User
Super User

Hey @Dunner2020 ,

 

the ALL function gives you back distinct combinations. These you can count then with the COUNTROWS function.

The following measure should work:

Amount distinct combinations = COUNTROWS( ALL( 'myTable'[id], 'myTable'[date] ) )

 

Let me know if that worked for you. If you need any help please let me know.

If I answered your question I would be happy if you could mark my post as a solution ✔️ and give it a thumbs up 👍
 
Best regards
Denis
 

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