Forum Discussion

ozlemv's avatar
ozlemv
Frequent Visitor
9 years ago
Solved

DistinctCount with filters

  Hi everyone,   Hoping I could have help on the below issue.   I would like to calculate the distinct company ids whose actuals are higher than a fixed value (X)   Here's the formula I used: ...
  • v-huizhn-msft's avatar
    v-huizhn-msft
    9 years ago

    Hi ozlemv,

    You use the IFERROR function in your formula, you create a calculated column based on my understanding.

    IFERROR(A,B) := IF(ISERROR(A), B, A)

    The following sub-formula in your formula is right. When the vTable1[Actuals]>X is ture, it will return a value, if the value of vTable1[Actuals] is 0, it will return 0, so the formula will return 0.

    CALCULATE( DISTINCTCOUNT(vTable1[CompanyID]),filter(vTable1,vTable1[Actuals]>X))


    As Mi2n posted, you will get the expected result using the solution given.

    If you have any other issue, please describe it clearly and sample data for further analysis.

    Best Regards,
    Angelia