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Anonymous's avatar
Anonymous
Not applicable
6 years ago
Solved

Distinct Sum

Hi all ,    I have three columns ,   Month    Amount   Rate Jan           95000        35 Jan             6552        35 Jan             1556       35 Jan           95000       35 Jan       ...
  • parry2k's avatar
    6 years ago

    Anonymous try this

     

    Measure = 
    DIVIDE ( 
    SUMX ( VALUES ( Table[Rate] ), CALCULATE ( MAX ( Table[Amount] ) ) ),
    MAX ( Table[Rate] )
    )

     

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