Forum Discussion
Default value - Current Month Value
Hi Team,
I have a requirement.
I have a card Visual. and Slicer for month.
1.when i open report, in a card visual it should show current month value as default.
2. when we select month in slicer it should filter accoordingly.
please help
Thanks in advance
- Anonymous2 years ago
Hi ghouse_peer ,
Below is my table:
The following DAX might work for you:
Measure 1 = SELECTEDVALUE('Table (2)'[Reporting]) Measure 2 = var dat1 = MONTH(TODAY()) var dat2 = MONTH('Table (2)'[Measure 1]) var result = CALCULATE( MIN('Table (2)'[MothValue]), FILTER('Table (2)',dat2 = dat1) ) var result2 = CALCULATE( MIN('Table (2)'[MothValue]), FILTER('Table (2)',dat2 <> dat1) ) var result1 = IF(dat1 = dat2 , result , result2) return result1The final output is shown in the following figure:
Best Regards,
Xianda Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
3 Replies
- Thennarasu_RResponsive Resident
Hi ghouse_peer
Try this Measure,
Measure= Var __AA=Calculate(Sum(Value column),Dimdate(Month)=Month(Today()))
Return
If(selectedvalue(Dimdate(Month)),Calculate(sum(value column),__AA))
Thanks ,
Thennarasu R- ghouse_peerPost Patron
Not working!!
Reporting Month Value Aug-23 -1.0 Spe-23 -2.8 Oct-23 -3.2 So now when i select card visual and take value in that and Reporting Month in slicer. At first it should show Oct-23 value i,e -3.2 without selecting any value in slicer.
But when we select month in slicer it should show value accordingly. Please check
- AnonymousNot applicable
Hi ghouse_peer ,
Below is my table:
The following DAX might work for you:
Measure 1 = SELECTEDVALUE('Table (2)'[Reporting]) Measure 2 = var dat1 = MONTH(TODAY()) var dat2 = MONTH('Table (2)'[Measure 1]) var result = CALCULATE( MIN('Table (2)'[MothValue]), FILTER('Table (2)',dat2 = dat1) ) var result2 = CALCULATE( MIN('Table (2)'[MothValue]), FILTER('Table (2)',dat2 <> dat1) ) var result1 = IF(dat1 = dat2 , result , result2) return result1The final output is shown in the following figure:
Best Regards,
Xianda Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.