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Anonymous's avatar
Anonymous
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7 years ago
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Dax Measure or Column for active datetimes this hour

Hi all,

I'm experimenting with data from my own agenda using the Microsoft Exchange datastream. 
This dataset contains multiple meetings with start and end dates by the hour, so what i would like to do is check wich meetings are currently active for today in this hour. 

Normally i would go for something like:
if(Calendar[startdate] = today(); "active"; "not active") 
But this solution only checks the date, and not the datetime.

Anyone got an idea on how to achieve this?
Thanks in advance!!!
Stan


  • Hi Anonymous 

    Please see the below.

    VAR dateTime = NOW()
    VAR TimeStart = DATEVALUE(dateTime) + TIME(INT(TIMEVALUE(dateTime) * 24), 0, 0)
    VAR TimeEnd = TimeStart + TIME(1, 0, 0)
    RETURN 
    IF(Calendar[startdate] => TimeStart && Calendar[startdate] < TimeEnd, "active", "not active") 

    Regards,
    Mariusz

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

2 Replies

  • Mariusz's avatar
    Mariusz
    Icon for Community Champion rankCommunity Champion

    Hi Anonymous 

    Please see the below.

    VAR dateTime = NOW()
    VAR TimeStart = DATEVALUE(dateTime) + TIME(INT(TIMEVALUE(dateTime) * 24), 0, 0)
    VAR TimeEnd = TimeStart + TIME(1, 0, 0)
    RETURN 
    IF(Calendar[startdate] => TimeStart && Calendar[startdate] < TimeEnd, "active", "not active") 

    Regards,
    Mariusz

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

  • Mariusz's avatar
    Mariusz
    Icon for Community Champion rankCommunity Champion

    Hi Anonymous 

    The below code will give you current meetings

    VAR CurrentDateTime = NOW()
    RETURN 
    IF(Calendar[startdate] => CurrentDateTime && Calendar[enddate] < CurrentDateTime, "active", "not active") 

    Regards,
    Mariusz

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.