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Anonymous's avatar
Anonymous
Not applicable
4 years ago
Solved

Dax If statement

Hello Looking to see If i can build the following If statemnet below. 

If the Sum of ID Number is < 2 then " $500", 

otherwise if the Sum of ID Number is between 2 and  then "$800"

Otherwise if the sum of ID Number is = > 6 " $1000", "Out of Range"

 

Result should be the Sum of the ID Number is "$1000"

 

 

Need Help
  • v-henryk-mstf's avatar
    v-henryk-mstf
    4 years ago

    Hi Anonymous ,

     

    I did a test. First, I separated the ID in the power query and got the sum. Then use if judgment on the desktop to find the result. The reference is as follows:

    M_ = 
IF (
    MAX ( 'Table'[sum_of_id] ) <= 2,
    "$500",
    IF (
        MAX ( 'Table'[sum_of_id] ) < 6
            && MAX ( 'Table'[sum_of_id] ) > 2,
        "$800",
        IF ( MAX ( 'Table'[sum_of_id] ) >= 6, "$1000", "out of range" )
    )
)


    Best Regards,
    Henry


    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

2 Replies

  • parry2k's avatar
    parry2k
    Super User
    4 years ago

    Anonymous based on the ID Number shown in the image, you need to extract number from ID which you can easily do in Power Query by using the split from transform tab. Once you have the number separated from the ID, you can use the SWITCH function to achieve your goal.

     

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  • v-henryk-mstf's avatar
    v-henryk-mstf
    Community Support
    4 years ago

    Hi Anonymous ,

     

    I did a test. First, I separated the ID in the power query and got the sum. Then use if judgment on the desktop to find the result. The reference is as follows:

    M_ = 
IF (
    MAX ( 'Table'[sum_of_id] ) <= 2,
    "$500",
    IF (
        MAX ( 'Table'[sum_of_id] ) < 6
            && MAX ( 'Table'[sum_of_id] ) > 2,
        "$800",
        IF ( MAX ( 'Table'[sum_of_id] ) >= 6, "$1000", "out of range" )
    )
)


    Best Regards,
    Henry


    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.