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Anonymous's avatar
Anonymous
Not applicable
2 years ago
Solved

DateDiff with time excluding weekends

Hi All, I have a date table and fact table which are connected to each other via one-to-many. I'm using the following dax to get the out put: #Days_Den = VAR _d = DATEDIFF([ExpectedSta...
Need Help
  • Anonymous's avatar
    Anonymous
    2 years ago

    Hi Anonymous ,

     

    Due to I don't know your data model, I will share a workaround by my sample.

    Tables:

    Date = ADDCOLUMNS(CALENDARAUTO(),"Year",YEAR([Date]),"Month",MONTH([Date]),"WeekDay",WEEKDAY([Date],2))

    Measure:

    #Days_Den = 

VAR _d = DATEDIFF(MAX('Table'[ExpectedStartDate]), MAX('Table'[ExpectedEndDate]), SECOND)
VAR _min = DIVIDE(_d,60)
VAR _hour = DIVIDE(_min,60)
VAR _day = DIVIDE(_hour,24)
VAR _weekend = CALCULATE(COUNT('Date'[Date]),FILTER('Date','Date'[WeekDay] in {6,7} && 'Date'[Date]>=MAX('Table'[ExpectedStartDate]) && 'Date'[Date]<= MAX('Table'[ExpectedEndDate])))

return 
_day - _weekend

    Result is as below.

     

    Best Regards,
    Rico Zhou

     

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Anonymous's avatar
Anonymous
Not applicable
2 years ago

Hi Anonymous ,

 

Due to I don't know your data model, I will share a workaround by my sample.

Tables:

Date = ADDCOLUMNS(CALENDARAUTO(),"Year",YEAR([Date]),"Month",MONTH([Date]),"WeekDay",WEEKDAY([Date],2))

Measure:

#Days_Den = 

VAR _d = DATEDIFF(MAX('Table'[ExpectedStartDate]), MAX('Table'[ExpectedEndDate]), SECOND)
VAR _min = DIVIDE(_d,60)
VAR _hour = DIVIDE(_min,60)
VAR _day = DIVIDE(_hour,24)
VAR _weekend = CALCULATE(COUNT('Date'[Date]),FILTER('Date','Date'[WeekDay] in {6,7} && 'Date'[Date]>=MAX('Table'[ExpectedStartDate]) && 'Date'[Date]<= MAX('Table'[ExpectedEndDate])))

return 
_day - _weekend

Result is as below.

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.