Forum Discussion

NicholasBowman's avatar
NicholasBowman
New Member
8 years ago

Date Formula

Currently trying to convert a person's birth date to the same month and day in the current year. I have used the date formula as such: Birth Date This Year = DATE(YEAR(today()),MONTH(contacts[Birth Date]),DAY(contacts[Birth Date])). The problem seems to be in the day component as if i substitute that argument with a normal integer then the formula pulls through the correct date and month. I am just a little confused why the month component of the formula would work but the same logic in the day component is causing an error?

5 Replies

  • MFelix's avatar
    MFelix
    Super User
    8 years ago

    Hi NicholasBowman,

     

    The formula you are using should be correct, is the format of the Birth Date correct? Is it configured in your model as a date?

     

    Regards,

    MFelix

    • NicholasBowman's avatar
      NicholasBowman
      New Member
      8 years ago

      Hi! Thanks for your response. The formatting is correct - if i simply use the DAY function then it correctly extracts the day, but when i insert that in to the overall date function if get the error that 'an argument of function 'date' has the wrong data type or the result is too large or too small'. I am using the same column to determine the birthday month and day, so am struggling to understand why within the date formula there is suddenly an error (it works perfectly in the month position of the formula)

  • v-jiascu-msft's avatar
    v-jiascu-msft
    Microsoft Employee
    8 years ago

    Hi NicholasBowman,

     

    I guess there could be a date like 2004/2/29 while we don't have 2/29 in the current year. Please try the formula below.

    Column 2 =
VAR yearNow =
    YEAR ( TODAY () )
VAR isLeapNow =
    IF (
        MOD ( yearNow, 4 ) = 0
            && MOD ( yearNow, 100 ) <> 0,
        1,
        IF ( MOD ( yearNow, 400 ) = 0, 1, 0 )
    )
RETURN
    IF (
        FORMAT ( [Date], "MMDD" ) = "0229"
            && isLeapNow <> 1,
        DATE ( 2100, 1, 1 ),  //change this part to what you like
        DATE ( yearNow, MONTH ( [Date] ), DAY ( [Date] ) )
    )

    leapyear

     

    Best Regards,

    Dale

    • NicholasBowman's avatar
      NicholasBowman
      New Member
      8 years ago

      Thanks, i did try this but ended up with the same error response. Tried to test it another way by using an if function to return a different result if the DAY(date) = 29, but that also resulted in the same error