Forum Discussion
Daily average in calculated column
Hi Community,
I'm trying to find a way to calculate a daily average of a hourly prices of a certain market on historic series of 5 years. I need it in a column once I need to take that figures for a further join table.
The data is in this "Sample Table":
| Date | Price |
| 2021-05-06 | 5 |
| 2021-05-06 | 3 |
| 2021-05-06 | 1 |
| 2021-05-06 | 1 |
| 2021-05-06 | 2 |
| 2021-05-05 | 2 |
| 2021-05-05 | 3 |
| 2021-05-05 | 1 |
| 2021-05-05 | 4 |
| 2021-05-05 | 5 |
And the desired output is this format:
| Date | Price | Daily avg |
| 2021-05-06 | 5 | 2.4 |
| 2021-05-06 | 3 | 2.4 |
| 2021-05-06 | 1 | 2.4 |
| 2021-05-06 | 1 | 2.4 |
| 2021-05-06 | 2 | 2.4 |
| 2021-05-05 | 2 | 3 |
| 2021-05-05 | 3 | 3 |
| 2021-05-05 | 1 | 3 |
| 2021-05-05 | 4 | 3 |
| 2021-05-05 | 5 | 3 |
I'm trying to use:
Daily Avg =
Hi Anonymous
take a look at the following solution:
Average by Day = CALCULATE ( AVERAGE ( 'Table'[Price] ), ALLEXCEPT ( 'Table', 'Table'[Date] ) )With kind regards from the town where the legend of the 'Pied Piper of Hamelin' is at home
FrankAT (Proud to be a Datanaut)
3 Replies
- FrankATCommunity Champion
Hi Anonymous
take a look at the following solution:
Average by Day = CALCULATE ( AVERAGE ( 'Table'[Price] ), ALLEXCEPT ( 'Table', 'Table'[Date] ) )With kind regards from the town where the legend of the 'Pied Piper of Hamelin' is at home
FrankAT (Proud to be a Datanaut) - amitchandakSuper User
Anonymous , Try a new column like
averageX(filter(Table, [Date] =earlier([Date])),[Price])
- AnonymousNot applicable
Thanks FrankAT and amitchandak for your tips and help!
Cheers