Forum Discussion
DISTINCT COUNT and GROUP BY
Hello
I have the data:
| A | 1 | 01/01/2020 |
| B | 2 | 02/01/2020 |
| C | 3 | 03/02/2020 |
| E | 4 | 04/02/2020 |
| D | 5 | 05/03/2020 |
| D | 6 | 06/03/2020 |
How can I calculate the distinct number of Col1, where Col2 is >2 and group the results by month?
So the result should be:
Jan=0
Feb=2
Mar=1
Thanks!
Hi Anonymous ,
Here are the steps you can follow：
1. Create calculated column.
Month = MONTH('Table'[Date]) Month_mmm = FORMAT([Date],"mmm")2. Create measure.
Measure = var _2=CALCULATE(DISTINCTCOUNT('Table'[Column1]),FILTER('Table','Table'[Column2]>2&&'Table'[Month]=MAX('Table'[Month]))) return IF(_2=BLANK(),0,_2)3. Result.
You can downloaded PBIX file from here.
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
4 Replies
- amitchandak
Super User
Anonymous , Create a measure like this
calculate(distinctcount(Table[col1]), filter(Table, Table[col2] >2))+0
ryan_mayuAnonymous
you can create a column
month = FORMAT('Table'[Column3],"mmm")then create a measure
Measure = CALCULATE(DISTINCTCOUNT('Table'[Column1]),FILTER('Table','Table'[Column2]>2))+0Hi Anonymous ,
Here are the steps you can follow：
1. Create calculated column.
Month = MONTH('Table'[Date]) Month_mmm = FORMAT([Date],"mmm")2. Create measure.
Measure = var _2=CALCULATE(DISTINCTCOUNT('Table'[Column1]),FILTER('Table','Table'[Column2]>2&&'Table'[Month]=MAX('Table'[Month]))) return IF(_2=BLANK(),0,_2)3. Result.
You can downloaded PBIX file from here.
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
