Forum Discussion

Anonymous's avatar
Anonymous
Not applicable
7 years ago
Solved

DAx Formula

Hello All,

 

Please help me with the below DAX formula

 

Target:

1. Need the client Distinct Client count. Example: A,B,C...

2. For cleints like "A" it should count the figures mentioned in column Bundle from the data format below.

 

Please let me know if you need further details

REgards,

chandra

Varun

Need Help
  • v-juanli-msft's avatar
    v-juanli-msft
    7 years ago

    Hi Anonymous 

    Is this problem sloved? 

    If it is sloved, could you kindly accept it as a solution to close this case?

    If not, please let me know.

     

    Based on your requirements, you could create two measures

    sum = CALCULATE(SUM(Table1[Bundle]),ALLEXCEPT(Table1,Table1[Client]))

discount = CALCULATE(DISTINCTCOUNT(Table1[Client]),ALL(Table1))

    Best Regards

    Maggie

4 Replies

  • Nolock's avatar
    Nolock
    Resident Rockstar
    7 years ago

    Hi Anonymous,

     

    there are many options depending on what exactly you expect.

    If you need a DAX expression for creating a new table which result is a sum of bundle over client, use GROUPBY:

    GroupedTable = 
GROUPBY (
    Table1;
    Table1[Client];
    "Sum Of Bundle"; SUMX ( CURRENTGROUP (); IF ( ISBLANK ( Table1[Bundle] ); 0; Table1[Bundle] ) )
)

    If you don't care that B, C, D, and E aren't a part of the result because they are BLANK, use the default summarization of Power BI, see screenshot below.

  • rocky09's avatar
    rocky09
    Solution Sage
    7 years ago

    try this

    Table = SUMMARIZE(Table1,Table1[Client],"Total Bundle",SUM(Table1[Bundle]))
  • v-juanli-msft's avatar
    v-juanli-msft
    Community Support
    7 years ago

    Hi Anonymous 

    Is this problem sloved? 

    If it is sloved, could you kindly accept it as a solution to close this case?

    If not, please let me know.

     

    Based on your requirements, you could create two measures

    sum = CALCULATE(SUM(Table1[Bundle]),ALLEXCEPT(Table1,Table1[Client]))

discount = CALCULATE(DISTINCTCOUNT(Table1[Client]),ALL(Table1))

    Best Regards

    Maggie