Forum Discussion
DAX Measure help
Hi,
I am trying to get all measures shown based on selection, I had trouble to show what I needed as the slicer or filter exclude all other records that I need.
What I want to do:
If a select shop B, I want to show, profit of the selected shop, compare to average in its region and compare to average in its state.
Desired result:
Shop B: $150
average of region 1 in CA = (100+150+230)/3 = $160
average of CA $205
Any help is much appreciated.
Hi Anonymous ,
We can use two measures to meet your requirement. One calculates the average of region, another calculates the average of state.
average of region = CALCULATE ( AVERAGE ( 'Table'[Profit] ), ALLSELECTED ( 'Table' ), ALL ( 'Table'[Shop] ) , 'Table'[Region] IN DISTINCT ( 'Table'[Region] ), 'Table'[State] IN DISTINCT ( 'Table'[State] ) )average of State = CALCULATE ( AVERAGE ( 'Table'[Profit] ), ALLSELECTED ( 'Table' ), ALL ( 'Table'[Shop] ) , 'Table'[State] IN DISTINCT ( 'Table'[State] ) )The result like this,
BTW, pbix as attached.
Best regards,
Community Support Team _ zhenbw
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 Replies
- amitchandakSuper User
Anonymous , Try a new measure like
avergageX(summarize(Table,Table[Shop],"_1",sum(Table[profit])),[_1])
- v-zhenbw-msftCommunity Support
Hi Anonymous ,
We can use two measures to meet your requirement. One calculates the average of region, another calculates the average of state.
average of region = CALCULATE ( AVERAGE ( 'Table'[Profit] ), ALLSELECTED ( 'Table' ), ALL ( 'Table'[Shop] ) , 'Table'[Region] IN DISTINCT ( 'Table'[Region] ), 'Table'[State] IN DISTINCT ( 'Table'[State] ) )average of State = CALCULATE ( AVERAGE ( 'Table'[Profit] ), ALLSELECTED ( 'Table' ), ALL ( 'Table'[Shop] ) , 'Table'[State] IN DISTINCT ( 'Table'[State] ) )The result like this,
BTW, pbix as attached.
Best regards,
Community Support Team _ zhenbw
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.