Forum Discussion
Create visual from filtered data
- 8 years ago
Hi
Thanks for helping.
What wound up working for me was the following:
primaryFiltered = CALCULATE(COUNT(Sheet1[Colour]), ALLEXCEPT(Sheet1, Sheet1[Substance], Sheet1[Population]))
secondaryCount = COUNT(Sheet1[Colour])
Regards, Mark.
Hi Skemaz,
You can use a calculated measure to achieve what you need but I need some clarity on points below to help you out:
- Where the following values are coming from 384 and 16???
- Are they in different columns?
- And how do you differentiate between horses and race values?
- 16/3....what does number 3 represent???
Regards
Abduvali
Hi Abduvali
Thanks for your prompt reply.
The user selects filters in the "Race Filters" this reduces the number shown in (2) in the screen-shot. The number is just a single value in a Card. I have edited the filters interactions so that the filters in "Race Filters" apply to card (2) and (1).
However, the filters in "Horse Filters" only affect (1) and not (2).
The value could come from any field, but I have used a count of the "age" field to get the number.
In the screen-shot, (4) shows 3 rows representing the Jockey and Horse combination which is the 3 you asked about.
Thanks, Mark.
- Abduvali8 years agoSkilled Sharer
OK then create 4 measures:
- Race Measure = Calculate(SUM(YourTable[YourValue]),YourTable[RaceColumn] = "Race")
- this will let you get you 384 value, its same as the way you filtering it only by Race in that card
- Horse Measure = Calculate(SUM(YourTable[YourValue]),YourTable[RaceColumn] = "Horse")
- this will let you get you 16 value, its same as the way you filtering it only by Horse in that card
- Then create 3rd measure:
- % Measure = [Race Measure] / [Horse Measure]
- then select display as Percentage from Modelling tab / Data type
- % Measure = [Race Measure] / [Horse Measure]
- For the last one you will need another measure:
- Jockey Measure = [Horse Measure] / Distinctcount(YourTable[JockeyColumn])
- then select display as Percentage from Modelling tab / Data type
- Jockey Measure = [Horse Measure] / Distinctcount(YourTable[JockeyColumn])
I hope this will help if you have any questions let me know.
Regards
Abduvali
- Skemaz8 years agoAdvocate IIThank you very much.
I'll check it out when I get back to my computer.
Greatly appreciated.
Regards, Mark. - Skemaz8 years agoAdvocate II
Hi Abduvali
Please review the screen-shots of my attempt to apply your proposed solution in the link below.
You advice will be greatly appreciated.
https://1drv.ms/i/s!Ai8u-AHGz6m3iax60HZWwL66RSxy9w
Description:
(1) "age" is a text field so I get the error shown in (1).
(2) I switch to a numeric field "race" (see (3) in screen-shots) and get a different error.
(4) I replace SUM with COUNT and in (5) I get a Blank result.
(6) I remove = "Race" from the measure and I get a result of 828 which matches my filter result :-)
(7) I filter and both results match (384) - still all good :-)
In the last screen-shot, (8) I select a filter that has interactions of filters set to not affect the card in (9).
It only impacts (10).
However it does impact the measure - see (11).
I need (11) to match up with (9).
Any ideas on how to do this?
Thanks, Mark.
- Skemaz8 years agoAdvocate II
Hi
Thanks for helping.
What wound up working for me was the following:
primaryFiltered = CALCULATE(COUNT(Sheet1[Colour]), ALLEXCEPT(Sheet1, Sheet1[Substance], Sheet1[Population]))
secondaryCount = COUNT(Sheet1[Colour])
Regards, Mark.
- Race Measure = Calculate(SUM(YourTable[YourValue]),YourTable[RaceColumn] = "Race")