Forum Discussion
Create new column checking on other columns data
Hello Community!
I have a Table with the first 2 columns of the following example (ID and Time_1), and I need to add a third column (Time_2), in order to get something like this:
| ID | Time_1 | Time_2 |
| 1 | 30 | 10 |
| 1 | 30 | 10 |
| 1 | 30 | 10 |
| 2 | 50 | 50 |
| 3 | 40 | 20 |
| 3 | 40 | 20 |
| 4 | 80 | 20 |
| 4 | 80 | 20 |
| 4 | 80 | 20 |
| 4 | 80 | 20 |
Taking ID = 15 as example, Time_2 should be calculated as 30/3 = 10 (30 is the value of Time_1 and 3 is how many times Order 15 is repeated).
I’d be grateful if I could get some help. Thanks in advance
Anonymous - Try this:
Time_2 = VAR __Time_1 = [Time_1] VAR __Num = COUNTROWS(FILTER('Table (18)',[ID]=EARLIER([ID]))) RETURN __Time_1/__NumPBIX is attached below sig. Table (18).
3 Replies
- nandicResident Rockstar
Anonymous ,
Try this formula:Time_2 =var _Id_Amount = CALCULATE(MIN('Table'[Time_1]),'Table'[ID]=EARLIER('Table'[ID]))var _Id_Count = CALCULATE(COUNTROWS('Table'),'Table'[ID]=EARLIER('Table'[ID]))RETURNDIVIDE(_Id_Amount,_Id_Count)- AnonymousNot applicable
Hi nandic
Thanks for your help.
But I am not getting the result I was expecting.
The column Time_2 shows me the Time_1 value.
Looks like _Id_Count is not counting the number of times the ID appears in the column.
I tried creating the column _Id_Count separatelly, and I get 1 as a result for each row.
In my example I should get something like:
I hope this is clear. Do you know what I should do?
Thanks again!
- Greg_DecklerCommunity Champion
Anonymous - Try this:
Time_2 = VAR __Time_1 = [Time_1] VAR __Num = COUNTROWS(FILTER('Table (18)',[ID]=EARLIER([ID]))) RETURN __Time_1/__NumPBIX is attached below sig. Table (18).