Forum Discussion
Create column with random values from list
Hi all,
I want to define a list a text values, and then create a new column which selects any value from that list.
Can anyone please tell me how to select any value from a list?
e.g. create a new column containing any values from {"Apples", "Bananas", "Pears"}
Anonymous
Please create a Rank column which display the location of text cell.
Rank = RANKX(Table1,Table1[Name],,ASC)
Then, we select any location according the random number between 1 to the max location. Use LOOKUPVALUE function grab the values.New Column = LOOKUPVALUE(Table1[Name],Table1[Rank],RANDBETWEEN(1,MAX(Table1[Rank])))
Please refer to the following screenshot.
Best Regards,
Angelia
8 Replies
Sounds like you are talking "M" Power Query language. If that is the case, you could use:
Number.Random
https://msdn.microsoft.com/en-us/library/mt253346.aspx
or
Number.RandomBetween:
https://msdn.microsoft.com/en-us/library/mt253327.aspx
If you want to do it in DAX, the only thing I can think of would be Sample:
https://msdn.microsoft.com/en-us/library/mt163692.aspx
- Same as we create sample data in excel, u just create one master table with 2 Column(id,text) and in fact table you add one column as reference column by random in range of id column of table master. After that make the relationship between 2 table.
Anonymous
Please create a Rank column which display the location of text cell.
Rank = RANKX(Table1,Table1[Name],,ASC)
Then, we select any location according the random number between 1 to the max location. Use LOOKUPVALUE function grab the values.New Column = LOOKUPVALUE(Table1[Name],Table1[Rank],RANDBETWEEN(1,MAX(Table1[Rank])))
Please refer to the following screenshot.
Best Regards,
AngeliaHi Anonymous ,
I am very happy for you have resolved your issue. You'd better mark the corresponding reply which will help others find the solution easily. Thank you very much.
Best Regards,
Angelia
Given your list of words, here's a method that creates another list that contains 1 million items randomly selected from the initial list:
let list = {"Apples", "Bananas", "Pears"}, shuffle = List.Generate( () => 1, each _ <= 1000000, each _ + 1, each list{Number.RoundDown( Number.RandomBetween(0, List.Count(list)) )} ) in shuffle
