Forum Discussion
Count values in specified date range
Hi Anonymous ,
According to your description, here are my steps you can follow as a solution.
(1) This is my test data.
(2)We can create a table.
Calendar = CALENDAR(DATE(2015,01,01),DATE(2019,06,30))
(3) We can create a measure.
Pre-Intervention Incident Count =
SUMX (
SUMMARIZE (
'ReportTable',
'ReportTable'[report_no],
"_1",
COUNTX (
FILTER (
'ReportTable',
'ReportTable'[date] >= MIN ( 'Calendar'[Date] )
&& 'ReportTable'[date] <= MAX ( 'Calendar'[Date] )
),
'ReportTable'[report_no]
)
),
[_1]
)
(4) Then the result is as follows.
If the above one can't help you get the desired result, please provide some sample data in your tables (exclude sensitive data) with Text format and your expected result with backend logic and special examples. It is better if you can share a simplified pbix file. Thank you.
Best Regards,
Neeko Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi Neeko,
Thank you for your response! That seemed to work, however I have two different date ranges I have to account for:
1/1/2015 - 6/30/2019
7/1/2019 - Present
How can I account for both date ranges with a single calendar table? The solution you provided would account for a single date range at a time.
Thank you!
- Anonymous3 years agoNot applicable
Hi Anonymous ,
According to your description, here are my steps you can follow as a solution.
(1) This is my test data.
(2) We can create two measures.
Pre-Intervention Incident Count (1/1/2015 - 6/30/2019) = SUMX ( SUMMARIZE ( 'ReportTable', 'ReportTable'[report_no], "_1", COUNTX ( FILTER ( 'ReportTable', 'ReportTable'[date] >= DATE ( 2015, 1, 1 ) && 'ReportTable'[date] <= DATE ( 2019, 6, 30 ) ), 'ReportTable'[report_no] ) ), [_1] )Pre-Intervention Incident Count (7/1/2019 - Present) = SUMX ( SUMMARIZE ( 'ReportTable', 'ReportTable'[report_no], "_1", COUNTX ( FILTER ( 'ReportTable', 'ReportTable'[date] >= DATE ( 2019, 7, 1 ) && 'ReportTable'[date] <= TODAY () ), 'ReportTable'[report_no] ) ), [_1] )(3) Then the result is as follows.
Best Regards,
Neeko Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.